Identify the molecularity of the reaction below: Br₂(g) → 2Br⁻(g)   A) unimolecular B) bimolecular C) termolecular D) quadmolecular

Consider these three reactions as the elementary steps in the mechanism for a chemical reaction.(i) Cl2 (g) + Pt (s) à 2Cl (g) + Pt (s) Ea = 1550 kJ ∆H = – 950 kJ(ii) Cl (g)+ CO (g) + Pt (s) à ClCO (g) + Pt (s) Ea = 2240 kJ ∆H = 575 kJ(iii) Cl (g) + ClCO (g) à Cl2CO (g) Ea = 2350 kJ ∆H = – 825 kJ  a. Draw the potential energy diagram for the reaction. Label the data points for clarity.The potential energy of the reactants is 600 kJ. b. What is the overall chemical equation? c. What is the overall change in enthalpy for the above chemical reaction? d. What is the overall amount of activation energy for the above chemical reaction? e. Which reaction intermediate would be considered a catalyst (if any) and why? f. If you were to add 2700kJ of activation energy to the reaction, would you be able to make the reaction reverse itself (i.e. have the products become reactants)? Justify your answer. g. If you were to added a positive catalyst to step (iii) what would the end result be? Justify…

Consider these three reactions as the elementary steps in the mechanism for a chemical reaction.(i) Cl2 (g) + Pt (s) à 2Cl (g) + Pt (s) Ea = 1550 kJ ∆H = – 950 kJ(ii) Cl (g)+ CO (g) + Pt (s) à ClCO (g) + Pt (s) Ea = 2240 kJ ∆H = 575 kJ(iii) Cl (g) + ClCO (g) à Cl2CO (g) Ea = 2350 kJ ∆H = – 825 kJ e. Which reaction intermediate would be considered a catalyst (if any) and why?f. If you were to add 2700kJ of activation energy to the reaction, would you be able to make thereaction reverse itself (i.e. have the products become reactants)? Justify your answer.g. If you were to added a positive catalyst to step (iii) what would the end result be? Justify yourprediction. h. Your friend is looking at your graph and states that she believes that step (ii) is the ratedetermining step. Do you agree with her? Justify your reasoning.

Consider these three reactions as the elementary steps in the mechanism for a chemical reaction. (i) H2(g) + NO(g) à H2O(g) + N(g) Ea = 436 kJ ∆H = –491 kJ (ii) N(g) + NO(g) à N2(g) + O(g) Ea = 625 kJ ∆H = –312 kJ (iii) O(g) + H2(g) à H2O(g) Ea = 1690 kJ ∆H = +131 kJ What is Ea for the overall reaction? You must calculate this from the potential energy diagram.

Consider these three reactions as the elementary steps in the mechanism for a chemical reaction. (i) H2(g) + NO(g) à H2O(g) + N(g) Ea = 436 kJ ∆H = –491 kJ (ii) N(g) + NO(g) à N2(g) + O(g) Ea = 625 kJ ∆H = –312 kJ ( iii) O(g) + H2(g) à H2O(g) Ea = 1690 kJ ∆H = +131 kJ What is the ∆H for the overall reaction? Overall, is it endothermic or exothermic?

Consider these three reactions as the elementary steps in the mechanism for a chemical reaction. (i) H2(g) + NO(g) à H2O(g) + N(g) Ea = 436 kJ ∆H = –491 kJ (ii) N(g) + NO(g) à N2(g) + O(g) Ea = 625 kJ ∆H = –312 kJ (iii) O(g) + H2(g) à H2O(g) Ea = 1690 kJ ∆H = +131 kJ Draw the potential energy diagram for the reaction. Assume the potential energy of the reactants was 1400 kJ

I get using the Arrhenius equation but even after calculating the e-[82.64 KJ/mol)/(8.314 J/mol.K × 346.63 K)] it doesn't equal up to 3.518× 10-13 s-1. Where did it come from if it didn't from from just that?

(a) A reaction 2 A →P has a second-order rate law with k = 3.50 × 10−4 dm3 mol−1s−1. Calculate the time required for the concentration of A to change from 0.260 mol dm−3 to 0.011 mol dm−3 (b) For the ideal gas reaction A + B ↔ 2C + 2D, it is given that ∆Gθ500= 1250 cal mol-1. If 1.0 mol of A and 1.0 mol of B are placed in a vessel at 500 K and P is held fixed at 1200 torr, calculate the equilibrium amount of A, B, C, and D.

Refer to the following potential energy diagram for the reaction: XY→ X+Y Potential Energy 400 300 200 100 100 kJ 400 kJ 200 kJ Reactants O-200 kJ 300 kJ Activated complex Reaction Pathway What is the enthalpy change (AH) for the reverse reaction: (a) (b) (c) Products

A NASA spacecraft measures the rate R of at which atmospheric pressure on Mars decreases with altitude. The result at a certain altitude is: - 1 R=0.0296 kPa·km -4 Convert r to j·cm ala 4 J•cm x10 18 Ar