Identifiers declared inside a block: scope { // block begins int x; // local in block x = 9; System.out.println (x) ; } // block ends have block scope, are called local variables and are visible only inside the block. Local variables in different blocks may have the same name. What is the output of the program? public static void main (String [] a) { int x; // local in main } } x = 1 ; System.out.println("Main x " + x); methodl () ; void methodl () { } System.out.println("Main x " + x); method2 () ; int x= 0; // local in method System.out.println ("methodl x"+ x); void method2 () { System.out.println ("method2 x"+ x);

Identifiers declared inside a block: scope { // block begins int x; // local in block x = 9; System.out.println (x) ; } // block ends have block scope, are called local variables and are visible only inside the block. Local variables in different blocks may have the same name. What is the output of the program? public static void main (String [] a) { int x; // local in main } } x = 1 ; System.out.println("Main x " + x); methodl () ; void methodl () { } System.out.println("Main x " + x); method2 () ; int x= 0; // local in method System.out.println ("methodl x"+ x); void method2 () { System.out.println ("method2 x"+ x);

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Description: I find these types of questions challenging due to a lack of understanding. Could you kindly provide a detailed and specific answer to assist me to answer the question below.question:Local variables in different blocks may have the same name. What is

Microsoft Visual C#

7th Edition

ISBN:9781337102100

Author:Joyce, Farrell.

Publisher:Joyce, Farrell.

Chapter8: Advanced Method Concepts

Section: Chapter Questions

Problem 8RQ

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When you move the pointer too quickly, a phenomena known as submarineing happens when the cursor vanishes.
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