I want the same solution, but with the mention ofquestions data and a detailed mathematicalsolution.5-27. Blood flows from the left ventricle (LV) of the heartwhich has an exit diameter of di = 16 mm, through thestenotic aortic valve of diameter d, = 8 mm, and then intothe aorta A having a diameter of dy = 20 mm. If the cardiacoutput is 4 liters per minute, the heart rate is 90 beats perminute, and each ejection of blood lasts 0.31 s, determinethe pressure drop over the valve. Take p, = 1060 kg/m².dsSOLUTIONThe volume of blood pumped per heartbeat is4 L/min90 beat/min1m= (0.04444 L/beat)44.44(10“) m²/beat1000 LThus, the discharge of blood by LV is+ _ 44.44(10*) m²/beat0.31 s/beat0.1434( 10-3) m²/sThen, the average velocities of the blood flow from the LV and into the Aorta; Vịand V3, respectively are0.1434(10³) m²/s = V½ [=(0.008 m)*]V = 0.7131 m/s0.1434(10-3) m²/s = V,[ #(0.01 m)*]Q = V¼A¡;%3D%3!Q = V3A;:%3DV3 = 0.4564 m/s%3DWriting Bernoulli's equation between the two points,P3 V2+ gz =+ gz3PbPbP11060 kg/m(0.7131 m/s)(0.4564 m/s)?+ 0P3+ 0 =21060 kg/m2Ap = P3 - Pi = 159 PaAns.

Answered: Image /qna-images/answer/daa83abd-077b-405f-8a05-0e45d3b1be9e.jpg

I want the same solution, but with the mention of questions data and a detailed mathematical solution. 5-27. Blood flows from the left ventricle (LV) of the heart which has an exit diameter of di = 16 mm, through the stenotic aortic valve of diameter d, = 8 mm, and then into the aorta A having a diameter of dy = 20 mm. If the cardiac output is 4 liters per minute, the heart rate is 90 beats per minute, and each ejection of blood lasts 0.31 s, determine the pressure drop over the valve. Take p, = 1060 kg/m². LV SOLUTION The volume of blood pumped per heartbeat is 4 L/min 90 beat/min (0.0444 L/beat) 1m 1000 L - 44.44(10*) m²/beat Thus, the discharge of blood by LV is + 44.44( 10“) m²/beat 0.31 s/beat 0.1434(10-3) m²/s Then, the average velocities of the blood flow from the LV and into the Aorta; V¡ and V3, respectively are 0.1434(10) m²/s = V; [ #(0.008 m)* ] Vị = 0.7131 m/s 0.1434(10-3) m²/s = V3[ =(0.01 m)*] Q = V,A;; %3D %3D Q = V½A;: V3 = 0.4564 m/s Writing Bernoulli's equation between the two points, P V? + gz = 2 2 + gz3 Pb Pb Pi (0.7131 m/s)² P3 (0.4564 m/s)² + 0 = 1060 kg/m³ 2 1060 kg/m A, = P3 - Pi = 159 Pa Ans. %3D

I want the same solution, but with the mention of questions data and a detailed mathematical solution. 5-27. Blood flows from the left ventricle (LV) of the heart which has an exit diameter of di = 16 mm, through the stenotic aortic valve of diameter d, = 8 mm, and then into the aorta A having a diameter of dy = 20 mm. If the cardiac output is 4 liters per minute, the heart rate is 90 beats per minute, and each ejection of blood lasts 0.31 s, determine the pressure drop over the valve. Take p, = 1060 kg/m². LV SOLUTION The volume of blood pumped per heartbeat is 4 L/min 90 beat/min (0.0444 L/beat) 1m 1000 L - 44.44(10) m²/beat Thus, the discharge of blood by LV is + 44.44( 10“) m²/beat 0.31 s/beat 0.1434(10-3) m²/s Then, the average velocities of the blood flow from the LV and into the Aorta; V¡ and V3, respectively are 0.1434(10) m²/s = V; [ #(0.008 m) ] Vị = 0.7131 m/s 0.1434(10-3) m²/s = V3[ =(0.01 m)*] Q = V,A;; %3D %3D Q = V½A;: V3 = 0.4564 m/s Writing Bernoulli's equation between the two points, P V? + gz = 2 2 + gz3 Pb Pb Pi (0.7131 m/s)² P3 (0.4564 m/s)² + 0 = 1060 kg/m³ 2 1060 kg/m A, = P3 - Pi = 159 Pa Ans. %3D

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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