i) The circular rod in Figure 3.1 is subjected to an axial force of 300 N. The length of the rod is 200 mm and its diameter is 7 mm. After loading the rod elongates by 1.2 mm and its circumference decreases by 0.05 mm, determine (a) the modulus of elasticity, (b) the Poisson's ratio, (c) the shear modulus of the rod's material. 300 N 300 N 200 mm

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State one word problem and solve it wherein the ideal mechanical advantage of a wedge is being solved. Use the formula, IMA = (Length of the Widge) divided by (Width of the Wedge). note: please do not forget to include your solution in solving the problem.

Table 1: Mechanical behavior of human cadaver tibial bones during pure torsional loads applied with the proximal tibia fixed and the torque applied to the distal tibia until there is bone fracture. Medial condyle Tibial tuberosity- Medial malleolus -Lateral condyle Head of fibula Ti-6Al-4V grade 5 Stainless Steel 316L Region of bone resection -Lateral malleolus L = 365 mm Annealed Annealed Torque at ultimate failure (bone fracture) Displacement (twist angle) at ultimate failure Torsional Stiffness Table 2: Mechanical properties of candidate materials for the rod. Material Process Yield Strength (MPa) 880 220-270 Do = 23 mm Elastic Modulus (GPa) 115 190 d₁ = 14 mm Figure 1: Representative tibia bone showing the resection region (blue arrows) and median length (L). A circular cross section of distal tibia taken at the level of resection) showing the median inner (di) and outer (Do) diameters of the cortical bone. A tibia bone after resection with the proposed metal solid rod (black line)…

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