I need help with my MATLAB code. I having problems with the double values of trig. For the following code, I should get both t1 and t_1 to be equal to 160 degrees, but I don't. t1 = 160 and t_1 = 20. I know that asind(b/sind(theta2)) could equal to both 160 degrees and 20 degrees. So, how do I create a program that will give me a value that t1 and t_1 will equal to. To be clear I would want a set of code that outputs 160 degrees in this case because t1 = 160 and t_1 = 20, 160. I want the output to be a value that t1 = t_1.     clc; clear all; theta1 = 160; theta2 = 35; a = cosd(theta1)*sind(theta2) b = sind(theta1)*sind(theta2) t1 = acosd(a/sind(theta2)) t_1 = asind(b/sind(theta2))

I need help with programming in MATLAB. The following code transforms cartesian coordinates to the kepler elements. Can you give me the code for transforming kepler orbital elements to cartesian coordinates. The following code gives the 6 kepler elements. Transform those elements into cartesian coordinate that match the values under the Example Usage part of the code. Can you send a screenshot so I know the output of your code matches the input of the following code? I have asked this question twice and I have gotten the exact same code as the answer and it did not match. Please make sure the results match.   % Example usage:x = 1000;   y = 2000;   z = 3000;   vx = 4;     vy = -3;    vz = 2;      [a, ecc, inc, raan, argp, f] = cart2orb(x, y, z, vx, vy, vz); % Display the resultsdisp(['Semi-Major Axis (a): ', num2str(a), ' km']);disp(['Eccentricity (ecc): ', num2str(ecc)]);disp(['Inclination (inc): ', num2str(inc), ' degrees']);disp(['Right Ascension of Ascending Node (raan): ',…

f(x) = 1/(1 + 25.a?) This is a somewhat famous function in numerical analysis because it displays interesting behavior when approximated using polynomial interpolation on uniformly spaced nodes. You are going write your own code for polynomial interpolation and investigate the accuracy of two approximations. Task: Do the following: 1. Write a function that takes an array containing n+1 distinct points and returns the coefficients a, k 0, 1, .. . , n for the Newton form of the interpolating polynomial for an arbitrary function. You can pass in either the function f(x) or an array of function values at the points. 2. Write a function that takes the Newton coefficients of the polynomial and a point r and evaluates P,(x). This should be the nested product form that is similar to Horner's method. 3. Write a program that calls your two functions to compute the interpolating polynomial for the specific function f(x) given above and does the following: (a) Using the 21 uniformly spaced nodes…

Need help in Matlab. How do I modify this program to produce eye shapes like the pink picture using scaling, rotating and translating? Thank you! figure(1) x(1:2,1)=[1;0]; plot(x(1), x(2),'*'); grid on; hold on; axis([-15 15 -15 15]); k=1; Inc=1; for j=1:Inc:360; x(1:2,k+1)=[cosd(Inc) -sind(Inc);sind(Inc) cosd(Inc)]*x(1:2,k); plot(x(1,k+1), x(2,k+1),'^'); k=k+1; %for j=1:Inc:360; %x(1:2,k+1)=[cosd(Inc) -sind(Inc);sind(Inc) cosd(Inc)]*x(1:2,k); %plot(x(1,k+1), x(2,k+1),'^'); %k=k+1; %pause(); end   for k=1:Inc:360; y1(1:2,k)=[1.5 0;0 3]*x(1:2,k); plot(y1(1,k),y1(2,k),'^') %for k=1:Inc:360; %y1(1:2,k)=[1.5 0;0 3]*x(1:2,k); %plot(y1(1,k),y1(2,k),'^') %pause(0.1); end   for k=1:Inc:360; y2(1:2,k)=[3 0;0 1.5]*x(1:2,k)+[7;5]; plot(y2(1,k),y2(2,k),'^') %for k=1:Inc:360; %y2(1:2,k)=[3 0;0 1.5]*x(1:2,k)+[7;5]; %plot(y2(1,k),y2(2,k),'^') %pause(0.1); end   for k=1:Inc:360; y3(1:2,k)=[3 0;0 1.5]*x(1:2,k)+[-7;5]; plot(y3(1,k),y3(2,k),'^') %for k=1:Inc:360; %y3(1:2,k)=[3 0;0 1.5]*x(1:2,k)+[-7;5];…