I need help creating an MIPS program that takes a user's input of three positive integers and outputs their greatest common prime factor. I have this so far but when instruction reaches the loop I get an error.

This is Machine Architecture! ***WRITE THE CODE ON YOUR OWN*** Create a MIPS program that demonstrates that the associative law fails in addition for floating point numbers (single or double precision). You only need to demonstrate it for single precision. Remember the associative law is a + (b + c) = (a + b) + c. The program’s output should look something like the following where the xxx’s are the numbers you chose. The resulting numbers may be different than mine depending on your choice of a, b, and c. Using a = xxx, b = xxx, and c = xxx a + (b + c) = 0 (a + b) + c = 1   The key is to have two of the number large (one positively and one negatively but equal in magnitude) floating point numbers and the third floating point number very small in comparison. As a side note, the associative law will also fail for multiplication for floating point numbers, but you do not need to demonstrate that. Please don't forget to include comments in this code

Task 1 Write a program that adds the three numbers stored in data registers at 0x20, 0x30, and Ox40 and places the sum in data register at 0x50. Step 1 Load the number of 0x20 into the WREG register Step 2 Add the number of 0x30 and the number in the WREG register and leave the sum in the WREG register. Step 3 Add the number of Ox40 and the number in the WREG register and leave the sum in the WREG register. Step 4 Store the contents of the WREG register in the memory location at 0x50. Modify the program in Task1, so the program will run in infinite loop by using these following functions: ii. BRA function

i have this code .ORIG x3000SetupLEA R0, InfoPUTS ADD R6, R6, #5; Init Main Loop counter (loop 5 times) ;Print first 2 Fib values before starting;----- Your Code Here -----;LD R1, #0   JSR printNum   LD R2, #1   JSR printNumJSR printNum    ; Print the value in R2   JSR printCommaSpace ; Print comma and space   ;----- End Your Code Here -----;;Loop and call subroutines to calculate each subsequent value in the sequence;Exit the loop once all single-digit values in the sequence have been printedMainLoop ;----- Your Code Here -----;   JSR calcNextFib   JSR printNum   JSR printCommaSpaceADD R6, R6, #-1BRz Done    BR MainLoop   ;----- End Your Code Here -----; Done HALT ;-----------------------------------;Subroutines;----------------------------------- ;Uses R1 and R2 to calc next value in Fibonacci sequence;When complete, Fib2 (R2) will contain the new Fib number;and Fib1 (R1) will contain the previous value of Fib2 (R2)calcNextFib;----- Your Code Here -----;ST R1, SaveR3 ; Save R1ST R2,…

This is Computer Machine Architecture! this is Hamming code in MIPS assembly language 1. when I input a 154 (the example in the book).  It should have given an output of 0x72A. the assignment: This assignment is to create a MIPS programs that the determines what the ECC code should given number (an 8-bit byte).  The codes you create are to work for 8-bit positive numbers as these are simpler to work with than larger numbers. The program is to request the user to enter a byte of data (a positive integer in the range of 0 to 255 in decimal) and then create the 12-bit Hamming code as described in your text (see above). The program is to then output this (with an appropriate label) in hex. Make sure that you have lots of comments in your code as this is in MIPS. Also make the code neat: line up the instruction columns, the register columns, and the comment fields like the format below

I get an error in LC3 assembly programming when i try to run this code. can someone explain how i can fix this and give me the solution to the fix. i will be very thankfull

What does this MIPS program do? - in english  addi $s0, $0, 0      addi $s1, $0, 1      addi $t0, $s0, 50 loop: beq $s0, $t0, done      add $s1, $s1, $s1      addi $s0, $s0, 2      j   loop done:

Please help me find the bug a MIPS assembly program that takes input of an integer and  prints out a string that shows how that integer should be encoded using 16 bits. Please help me find the bug It is supposed to handle both positive and negative valued inputs. The program should also print out an error message if the given input cannot be expressed as a 16 bit signed integer.   As an example, if the input is 12, the program should output 0000000000001100.   The error I get is Error in H:\Downloads\hw2221 line 24 column 10: "input": operand is of incorrect type     The program is  .datainput: .word 0output: .asciiz ""str1: .asciiz " Please enter an integer: ".text.globl main main: li $v0, 5syscall sw $v0, inputli $t1, 16li $t0, 0loop:beq $t1, $t0, endlw $t2, inputand $t2, $t2, 1sll $t2, $t2, 31or $t2, $t2, $t3srl $t3, $t3, 1srl $t2, input, 1sw $t2, inputaddi $t0, $t0, 1j loopend:move $a0, $t3li $v0, 1syscallli $v0, 10syscall

Which instruction loads ST(0) with an integer?