College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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I launch a ball with an initial velocity of 28.0 m/s with an angle of elevation of 35.0°. What are the components of the initial velocity?
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- A cannon ball is fired with an initial velocity vo at a wall that is 100. meters tall and located 450. meters away. The initial angle of launch of the cannon ball is 0. We want to determine if the cannon ball will clear the wall. If not how high-up will the ball strike the wall from the ground. (A) Sketch a graph showing position of the cannonball during its flight (y versus x) showing and labeling the initial velocity vector. Identify and write knowns and unknowns (B) Without using numerical values, determine which physics equations of motion will help solve this problem. Simplify as useful for this particular case. (C) If the initial horizontal component of the balls velocity is 90.0 m/s and its initial angle is 0-24 degrees, does the cannonball clear the wall? If not, how high above the ground is the ball when it hits the wall?arrow_forwardA cannonball is shot with an initial speed of 30.0 m/s and 25.0º angle below horizontal from a height of 12.0 m. How far can the cannonball go horizontally when it lands on the ground, in meters? Use g = 10.0 m/s2. (Hint: Clearly label quantities along x- and y- components and write down all steps.)arrow_forwardA projectile is launched from point A with speed vo = 38 m/s. Determine the value of the launch angle a which maximizes the range R indicated in the figure. Determine the corresponding value R. Vo = 38 m/s A Answers: α = α R= i i 127 m- 15.8 m R 3 Barrow_forward
- A batter hits the baseball A with an initial velocity of vo = 91 ft/sec directly toward fielder B at an angle of 38° to the horizontal; the initial position of the ball is 2.4 ft above ground level. Fielder B requires 0.24 sec to judge where the ball should be caught and begins moving to that position with constant speed. Because of great experience, fielder B chooses his running speed so that he arrives at the "catch position" simultaneously with the baseball. The catch position is the field location at which the ball altitude is 7.9 ft. Determine the velocity of the ball relative to the fielder at the instant the catch is made. Vo 438° 2.4' Answer: VA/B = (i 204' B i+ i Next question j) ft/secarrow_forwardThe initial speed of the ball is v0 = 22.2 m/s, the angle the ball is hit at is θ = 43o, and g = 8.4. How far away does the ball hit the ground?arrow_forwardA soccer ball is kicked horizontally off a 22.0 m high cliff and lands at a distance of 35.0 m from the base of the cliff. Determine the initial horizontal velocity of the soccer ball. What is the final velocity and direction of the ball?arrow_forward
- A projectile is launched with an initial velocity of 24.0 m/s at an angle of 30.0° elevation. What are the components of the velocity of the projectile after 2.00 s?arrow_forwardA cannonball is shot with an initial speed of 30.0 m/s and 25.0º angle above horizontal from a height of 12.0 m. How far can the cannonball go horizontally when it lands on the ground, in meters? Use g = 10.0 m/s2. (Hint: Clearly label quantities along x- and y- components and write down all steps.)arrow_forwardA lizard kicks a ball with an initial velocity of 10 m/s at an angle of 35º with the horizontal. What is the maximum height of the ball?arrow_forward
- I don’t know what to do next. Please helparrow_forwardA projectile's launch speed is 6.30 times its speed at maximum height. Find the launch angle θ0.arrow_forwardA projectile is launched from and returns to ground level, as the figure shows. There is no air resistance. The horizontal range of the projectile is measured to be R= 177 m, and the horizontal component of the launch velocity is vox = 22.0 m/s. Find the vertical component voy of the projectile. +v voy Var=+22.0m/s to +x Number i R=177 m Unitsarrow_forward
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