Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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![### Determining the Molality and Molarity of a Sodium Chloride Solution
In this educational exercise, you will determine the molality and molarity of a sodium chloride (NaCl) solution. The solution is prepared by adding 216.0 grams of solid NaCl to 612.0 grams of water. The density of the resultant saline solution is 1.1972 grams per milliliter (g/mL).
**Given Data:**
- Mass of NaCl = 216.0 g
- Mass of water = 612.0 g
- Density of saline solution = 1.1972 g/mL
**Formulas to Use:**
1. **Molality (m)**:
\[
\text{molality (m)} = \frac{\text{moles of solute}}{\text{mass of solvent (kg)}}
\]
2. **Molarity (M)**:
\[
\text{molarity (M)} = \frac{\text{moles of solute}}{\text{volume of solution (L)}}
\]
To find these quantities, follow these steps:
1. **Calculate the Moles of NaCl**:
- Molar mass of NaCl = 58.44 g/mol
- Moles of NaCl = \(\frac{216.0 \text{ g}}{58.44 \text{ g/mol}}\)
2. **Convert the Mass of Water to Kilograms**:
- Mass of water (kg) = \(\frac{612.0 \text{ g}}{1000}\)
3. **Determine the Volume of the Solution**:
- Total mass of solution = mass of NaCl + mass of water
- Volume of solution (mL) = \(\frac{\text{total mass}}{\text{density}}\)
- Convert volume from mL to L
4. **Calculate Molality**:
\[
\text{molality (m)} = \frac{\text{moles of NaCl}}{\text{mass of water (kg)}}
\]
5. **Calculate Molarity**:
\[
\text{molarity (M)} = \frac{\text{moles of NaCl}}{\text{volume of solution (L)}}
\]
**Input Fields:**
- **](https://content.bartleby.com/qna-images/question/7eaef044-20a7-420f-b57c-5d0c5f8d0743/5b6585ee-73db-4cff-99d4-25c4da29cd9d/4lms3k8_reoriented.jpeg)
Transcribed Image Text:### Determining the Molality and Molarity of a Sodium Chloride Solution
In this educational exercise, you will determine the molality and molarity of a sodium chloride (NaCl) solution. The solution is prepared by adding 216.0 grams of solid NaCl to 612.0 grams of water. The density of the resultant saline solution is 1.1972 grams per milliliter (g/mL).
**Given Data:**
- Mass of NaCl = 216.0 g
- Mass of water = 612.0 g
- Density of saline solution = 1.1972 g/mL
**Formulas to Use:**
1. **Molality (m)**:
\[
\text{molality (m)} = \frac{\text{moles of solute}}{\text{mass of solvent (kg)}}
\]
2. **Molarity (M)**:
\[
\text{molarity (M)} = \frac{\text{moles of solute}}{\text{volume of solution (L)}}
\]
To find these quantities, follow these steps:
1. **Calculate the Moles of NaCl**:
- Molar mass of NaCl = 58.44 g/mol
- Moles of NaCl = \(\frac{216.0 \text{ g}}{58.44 \text{ g/mol}}\)
2. **Convert the Mass of Water to Kilograms**:
- Mass of water (kg) = \(\frac{612.0 \text{ g}}{1000}\)
3. **Determine the Volume of the Solution**:
- Total mass of solution = mass of NaCl + mass of water
- Volume of solution (mL) = \(\frac{\text{total mass}}{\text{density}}\)
- Convert volume from mL to L
4. **Calculate Molality**:
\[
\text{molality (m)} = \frac{\text{moles of NaCl}}{\text{mass of water (kg)}}
\]
5. **Calculate Molarity**:
\[
\text{molarity (M)} = \frac{\text{moles of NaCl}}{\text{volume of solution (L)}}
\]
**Input Fields:**
- **
Expert Solution
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Step 1
Molality is equal to the number of moles of solute dissolved in per kg of solvent.
It is denoted by m.
Its SI unit is mol/kg.
Formula used:
Molarity is equal to the number of moles of solute dissolved in per litre of solution.
It is denoted by M.
Its SI unit is mol/L.
Formula used:
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Step 2
To determine molaltiy of NaCl solution.
Mass of solvent = 612g =0.612kg.
Answer: Molality of the NaCl solution is 6.029mol/kg
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