W. Practice 4 - CHEM 1201 X co Course: 2020 Spring CHEM b My Questions | bartleby A https://www.webassign.net/web/Student/Assignment-Responses/randomize?pos=13&dep=22671454&tags=autosave#question361047_13 ... 14. 0/0 POINTS PREVIOUS ANSWERS 21/100 Submissions Used MY NOTES ASK YOUR TEACHER Calculate the rms (average) speed of N, atoms or molecules at 118 °C. Use R = 8.314 kg-m2/K-s2-mol for the value of the gas constant. O a) The average speed of a N, atom/molecule at 118 °C is 348 m/s. O b) The average speed of a N, atom/molecule at 118 °C is 10.3 m/s. O c) The average speed of a N2 atom/molecule at 118 °C is 265 m/s. O d) The average speed of a N2 atom/molecule at 118 °C is 590. m/s. O e) The average speed of a N2 atom/molecule at 118 °C is 18.7 m/s. 15. 0/0 POINTS PREVIOUS ANSWERS 21/100 Submissions Used MY NOTES ASK YOUR TEACHER sulfur dioxide was allowed to effuse through a small opening under constant pressure conditions. It required 699 s for 1.00 L of this gas to effuse. Calculate the effusion time of hydrogen (H2) under identical experimental conditions. (Remember that the faster the rate of effusion, the shorter the time required for effusion; that is, rate and time are inversely proportional.) a) The effusion time is 124 s. b) The effusion time is 22.0 s. 3:49 AM e Type here to search 4/10/2020
W. Practice 4 - CHEM 1201 X co Course: 2020 Spring CHEM b My Questions | bartleby A https://www.webassign.net/web/Student/Assignment-Responses/randomize?pos=13&dep=22671454&tags=autosave#question361047_13 ... 14. 0/0 POINTS PREVIOUS ANSWERS 21/100 Submissions Used MY NOTES ASK YOUR TEACHER Calculate the rms (average) speed of N, atoms or molecules at 118 °C. Use R = 8.314 kg-m2/K-s2-mol for the value of the gas constant. O a) The average speed of a N, atom/molecule at 118 °C is 348 m/s. O b) The average speed of a N, atom/molecule at 118 °C is 10.3 m/s. O c) The average speed of a N2 atom/molecule at 118 °C is 265 m/s. O d) The average speed of a N2 atom/molecule at 118 °C is 590. m/s. O e) The average speed of a N2 atom/molecule at 118 °C is 18.7 m/s. 15. 0/0 POINTS PREVIOUS ANSWERS 21/100 Submissions Used MY NOTES ASK YOUR TEACHER sulfur dioxide was allowed to effuse through a small opening under constant pressure conditions. It required 699 s for 1.00 L of this gas to effuse. Calculate the effusion time of hydrogen (H2) under identical experimental conditions. (Remember that the faster the rate of effusion, the shorter the time required for effusion; that is, rate and time are inversely proportional.) a) The effusion time is 124 s. b) The effusion time is 22.0 s. 3:49 AM e Type here to search 4/10/2020
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:W. Practice 4 - CHEM 1201 X
co Course: 2020 Spring CHEM
b My Questions | bartleby
A https://www.webassign.net/web/Student/Assignment-Responses/randomize?pos=13&dep=22671454&tags=autosave#question361047_13
...
14.
0/0 POINTS
PREVIOUS ANSWERS
21/100 Submissions Used
MY NOTES
ASK YOUR TEACHER
Calculate the rms (average) speed of N, atoms or molecules at 118 °C. Use R = 8.314 kg-m2/K-s2-mol for the value of the gas constant.
O a) The average speed of a N, atom/molecule at 118 °C is 348 m/s.
O b) The average speed of a N, atom/molecule at 118 °C is 10.3 m/s.
O c) The average speed of a N2 atom/molecule at 118 °C is 265 m/s.
O d) The average speed of a N2 atom/molecule at 118 °C is 590. m/s.
O e) The average speed of a N2 atom/molecule at 118 °C is 18.7 m/s.
15.
0/0 POINTS
PREVIOUS ANSWERS
21/100 Submissions Used
MY NOTES
ASK YOUR TEACHER
sulfur dioxide was allowed to effuse through a small opening under constant pressure conditions. It required 699 s for 1.00 L of this gas to effuse. Calculate the effusion time of hydrogen
(H2) under identical experimental conditions. (Remember that the faster the rate of effusion, the shorter the time required for effusion; that is, rate and time are inversely proportional.)
a) The effusion time is 124 s.
b) The effusion time is 22.0 s.
3:49 AM
e Type here to search
4/10/2020
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