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I am working on question 25 of chapter 2 in the chemistry openstax second edition.  The question is what were the percent abundances of two isotopes in if they give two different atomic masses depending on where they are from. I believe I figured out how to write the math equation for it, but I don't know how to solve the equation. 10.807 = (10.0129*x) + (11.0931 * (1-x)) 10.819 = = (10.0129*x) + (11.0931 * (1-x)) I looked up the explanation in the solutions, and my equation looks right, but I have no idea how they solved the algebra portion.

I am working on question 25 of chapter 2 in the chemistry openstax second edition.  The question is what were the percent abundances of two isotopes in if they give two different atomic masses depending on where they are from. I believe I figured out how to write the math equation for it, but I don't know how to solve the equation. 10.807 = (10.0129*x) + (11.0931 * (1-x)) 10.819 = = (10.0129*x) + (11.0931 * (1-x)) I looked up the explanation in the solutions, and my equation looks right, but I have no idea how they solved the algebra portion.

Chemistry for Engineering Students
Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter2: Atoms And Molecules
Section: Chapter Questions
Problem 2.90PAE: 2.90 Naturally occurring europium has an average atomic weight of 151.964 amu. If the only isotopes...
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I am working on question 25 of chapter 2 in the chemistry openstax second edition.  The question is what were the percent abundances of two isotopes in if they give two different atomic masses depending on where they are from.

I believe I figured out how to write the math equation for it, but I don't know how to solve the equation.

10.807 = (10.0129*x) + (11.0931 * (1-x))

10.819 = = (10.0129*x) + (11.0931 * (1-x))

I looked up the explanation in the solutions, and my equation looks right, but I have no idea how they solved the algebra portion.

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