I am getting stuck with finding the mols, grams and percent of Cr^3+

Fundamentals Of Analytical Chemistry
9th Edition
ISBN:9781285640686
Author:Skoog
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Chapter26: Molecular Absorption Spectrometry
Section: Chapter Questions
Problem 26.31QAP
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I am getting stuck with finding the mols, grams and percent of Cr^3+.
by Mon
Subnit
Name
Date
Preparation and Analysis of a Purple Nickel Compound
Prelab
2.0184 g of a compound of the general formula Crx(NH3),Clz was prepared using 3.5246 g CrCl3
6 H2O and 10.00 mL of 15 M NH3. It was then analyzed as follows:
Analysis of Cr3+
The concentration of Cr³* was determined spectrophotometrically. The chromium(III) ion is
purple, with a maximum light absorption at 570 nm. A stock solution (Solution 1) of 0.100 M
Cr* was used to make the following dilutions:
Solution 2: 10.00 mL stock solution diluted to a total volume of 100 mL with water.
Solution 3: 20.00 mL stock solution diluted to a total volume of 100 mL with water.
1.2532 g of the unknown chromium compound was dissolved in enough water to make 100 mL
of solution. Absorbance readings are given below:
34
Solution 2
0.100M(10MC)=X 10oml
X= 0.01M
Colution 3
Absorbance
Concentration
0:1com
0.01M
0.02M
0.06m
Calculate the concentration of Cr** in solutions 2 and 3, Then, make a graph of absorbance vs.
concentration using the three known (standard) solutions. From the graph, find the concentration
of the chromium compound, calculate moles of Cr³*, grams of Cr³*, and % Cr³* in the unknown
Solution
1.850
1
0.187
0.374
3
1.122
unknown compound
compound. Attach graph and show work below.
3t 6.00mol
0.0GM OF
Answers:
0.0GM
mol/L Cr* (from graph)
mol Cr+
g Cr3+
% Cr+
shot on moto g' power
Crystal H.
73
Transcribed Image Text:by Mon Subnit Name Date Preparation and Analysis of a Purple Nickel Compound Prelab 2.0184 g of a compound of the general formula Crx(NH3),Clz was prepared using 3.5246 g CrCl3 6 H2O and 10.00 mL of 15 M NH3. It was then analyzed as follows: Analysis of Cr3+ The concentration of Cr³* was determined spectrophotometrically. The chromium(III) ion is purple, with a maximum light absorption at 570 nm. A stock solution (Solution 1) of 0.100 M Cr* was used to make the following dilutions: Solution 2: 10.00 mL stock solution diluted to a total volume of 100 mL with water. Solution 3: 20.00 mL stock solution diluted to a total volume of 100 mL with water. 1.2532 g of the unknown chromium compound was dissolved in enough water to make 100 mL of solution. Absorbance readings are given below: 34 Solution 2 0.100M(10MC)=X 10oml X= 0.01M Colution 3 Absorbance Concentration 0:1com 0.01M 0.02M 0.06m Calculate the concentration of Cr** in solutions 2 and 3, Then, make a graph of absorbance vs. concentration using the three known (standard) solutions. From the graph, find the concentration of the chromium compound, calculate moles of Cr³*, grams of Cr³*, and % Cr³* in the unknown Solution 1.850 1 0.187 0.374 3 1.122 unknown compound compound. Attach graph and show work below. 3t 6.00mol 0.0GM OF Answers: 0.0GM mol/L Cr* (from graph) mol Cr+ g Cr3+ % Cr+ shot on moto g' power Crystal H. 73
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