Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN: 9780133923605
Author: Robert L. Boylestad
Publisher: PEARSON
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Use Simple Circuit Methods (KVL, KCL, CDR, VDR, and Ohm’s law) only to determine the power of the 3iy-source. Is it active or passive? Explain your reasoning.
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- d) A regulator as shown in Figure 4 has an input voltage, Vs 12 V. The duty cycle, k = 0.35 and the switching frequency is 30 kHz. It also has an inductance, L= 200 µH, filter capacitance, C = 440 µF. The average load current, la = 1.25 A. Determine the; i. average output voltage, Va. ii. peak-to-peak output ripple voltage, AVc. iii. peak-to-peak output ripple current of inductor, AI. iv. peak current of the transistor, Ip. v. critical values of L and C. vi. critical values of L and C if Vs is increased to 14 V. Estimate the change in percentage for the critical values of L and C. V, Load V V G Figure 4arrow_forwardRI Rz Vo %3D 2R.R.CG. REZ 1.+ Redrawthe circuit-equivalentwhenoperatingat-a-DC-voltage(0Hz).1 VerifyusingKCL-that-the circuit-operation will-be-that-of a-non-invertingamplifier. 2.→ Redrawthe circuit-equivalentat-veryhigh-frequencies.-VerifythatVoutisshorted.-(Hint.-Note- thereactance at-thenon-invertinginputat-extremelyhighfrequencies.--What-will-bethe- voltage at-that-node?-What-doesthis-meanfor-the voltage at-Rf2?)1 3.+ Let-C1=C2..-Calculate thevaluesofC1-and-C2-for-a-cut-offfrequency of500-Hz-if-R1-and-R2. are-33kohm-and-choosereasonablevaluesof Rf1 and-RF2•50-thatthe-gain-at-low-frequenciesis- 4-dB.--1 4.→ Simulate the circuit-on-Multisim-andrepeatsteps4-and5-of-Part-1-again.--Produce its-Bode Plot- using-the AC-Sweepfunction.-Identify-the type of responsecurve andtheroll-offrate. +,arrow_forwardA Phase Modulator has a phase deviation constant, Kp = 35°/V. The carrier signal is ec = 8 cos2n(800k)t, volts and the modulating signal is em = 5 sin2r(2000)t, volts. a. What is the equation of the PM signal? b. What is the maximum phase deviation? c. what is the amount of deviation in the carrier phase angle at t = 160µs?arrow_forward
- Figure 2 shows a typical BJT amplifier, with its parasitic capacitances displayed. The current gain of the transistor is B=150 and the voltage gain of the amplifier is Am =-125. The small signal resistances of the transistor are re =16 ohm and r0 = infinity, respectively. The values of resistors and capacitors in the figure are: R1 =80 kohm, R2 =20 Kohm, Rc = 2 Kohm, RE = 2 Kohm, Rs =50 W, RI=5 kohm, Cs=2 uF, Cc=2 uF, Ce =10 uF, Cbc =4 pF, Cbe = 10 pF, Cce =1 pF, Cwi = 4 pF, CWO = 9 pF, and Vcc = 20 V. a) Sketch a simplified circuit diagram of Figure 2 for high frequency analysis. b) Using the concept of "Miller effect capacitance", calculate the input and Output Miller effect capacitances of Figure 2, respectively. C) Determine the upper cut-off frequency of Figure 2 that is imposed by its input network only. d) Explain briefly the possible ways to increase the upper cut-off frequencv of this amplifier.arrow_forwardSubject: Analogy Electronic and Circuit Derive Output Impedance & Voltage Gain for self bias un-bypass circuit using hybrid modelarrow_forwardplease solvearrow_forward
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