Hydrogen bromide dissociates into its gaseous elements,H₂ andBr2, at elevated temperatures.HBr(g)H₂(g)Br₂(g)AH, kJ/mol S, J/(mol-K)-36.44030.91198.6130.6245.3a. Calculate the percent dissociation at 373°C and 1.00 atm.(Enter your answer to three significant figures.)Percent dissociation =%Submit Answerb. What would be the percent dissociation at 373°C and 10.0 atm?(Enter your answer to three significant figures.)Percent dissociation =%c. Use data above and any reasonable approximation to obtain K.(Enter your answer to three significant figures.)K=Try Another Version9 item attempts remaining

When equillibrium constants are written in terms of pressure, is called Kp and when written in terms…

Hydrogen bromide dissociates into its gaseous elements, H₂ and Br₂, at elevated temperatures. HBr(g) H₂ (9) Br₂(g) AH, kJ/mol S, J/(mol-K) -36.44 0 30.91 198.6 130.6 245.3 a. Calculate the percent dissociation at 373°C and 1.00 atm. (Enter your answer to three significant figures.) Percent dissociation = % b. What would be the percent dissociation at 373°C and 10.0 atm? (Enter your answer to three significant figures.) Percent dissociation: = % c. Use data above and any reasonable approximation to obtain K. (Enter your answer to three significant figures.) K=

Hydrogen bromide dissociates into its gaseous elements, H₂ and Br₂, at elevated temperatures. HBr(g) H₂ (9) Br₂(g) AH, kJ/mol S, J/(mol-K) -36.44 0 30.91 198.6 130.6 245.3 a. Calculate the percent dissociation at 373°C and 1.00 atm. (Enter your answer to three significant figures.) Percent dissociation = % b. What would be the percent dissociation at 373°C and 10.0 atm? (Enter your answer to three significant figures.) Percent dissociation: = % c. Use data above and any reasonable approximation to obtain K. (Enter your answer to three significant figures.) K=

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

Which of the following changes will result in an increase in the amount of phosphorous pentachloride formed?
physical chem
Consider the reaction: N₂O4 (9) — 2NO2 (9) Write the equilibrium constant for this reaction in terms of the equilibrium constants, K₁ and K2, for the reactions below: N₂(g) +202 (g) = N₂O4 (9) K₁ 1/2N₂(g) + O2(g) — NO2(g) K₂ For answers with both a subscript and a superscript, enter the subscript first. For example, enter Kif the first equilibrium constant should be squared. K=
1. Calculate the numerical value of Kc at 193°C for this reaction: 3W (s) + 18 HCI (g) = 3WCl6 (g) +9H₂ (g) 2. At 1225°C, Kc= 2.6x10⁹ for the following reaction: 2BrFs (g) Br₂ (g) + 5F₂ (g) At equilibrium, it is determined that the following are present in a 7.25L container: 0.0333 mole BrF5 0.0777 mole Br₂ How many moles of F₂ are in the container at equilibrium?
Consider the reaction: N₂O4 (9) 2NO2(g) Write the equilibrium constant for this reaction in terms of the equilibrium constants, K₁ and K₂, for the reactions below: N2(g) + 202 (9) ⇒N₂O4(9) K₁ 1/2N₂(g) + O₂(g) NO₂ (g) K₂ For answers with both a subscript and a superscript, enter the subscript first. For example, enter Kif the first equilibrium constant should be squared. K
Hydrogen bromide dissociates into its gaseous elements, H2 and Brg, at elevated temperatures. AH, kl/mol S", J/(mol·K) HBr(9) -36.44 198.6 H2 (9) 130.6 Bra (9) 30.91 245.3 a. Calculate the percent dissociation at 383°C and 1.00 atm. (Enter your answer to three significant figures.) Percent dissociation % b. What would be the percent dissociation at 383°C and 10.0 atm? (Enter your answer to three significant figures.) Percent dissociation c. Use data above and any reasonable approximation to obtain К. (Enter your answer to three significant figures.) K=
Give typed full explanation not a single word hand written otherwise leave it
The standard Gibbs free energy, ∆??, is:a) The residual energy present in the reactants in the equilibrium stateb) The residual energy present in the products in the equilibrium statec) The difference in the residual energy of the reactants and products inBalance.d) The energy required to convert one mole of reactants into one mole ofproducts[justify the answer you consider correct]
Calculate A,G° at 25 °C for the formation of 1.00 mol of C2H5 OH(g) from C2H4(g) and H20(g). Use this value to calculate K, for the equilibrium. C2H4 (g) + H2O(g) 2 C,H;OH(g) Use the following data: kJ A;G*, mol C2H4 (g) H2O(g) C2H; OH(g) 68.35 -228.59 -168.49 Kp The v value of A,G' and the v value of Kp indicate that the reaction is product-favored.
can you help the question?
Give typed full explanation not a single word hand written otherwise leave it
Alert for not submit AI generated answer. I need unique and correct answer. Don't try to copy from anywhere. Do not give answer in image and hand writing