How much heat must be added to 900 grams of water at 100°C to make it steam at 100°C? (The latent heat for vaporization of water is 539 cal /g).

You wish to cool a 1.59 kg block of tin initially at 96.0°C to a temperature of 57.0°C by placing it in a container of kerosene initially at 28.0°C. Determine the volume (in L) of the liquid needed in order to accomplish this task without boiling. The density and specific heat of kerosene are respectively 820 kg/m³ and 2,010 J/(kg °C), and the specific heat of tin is 218 J/(kg °C). L Need Help? Read It

The same amount of heat entering identical masses of different substances produces different temperature changes. Calculate the final temperature when 1.70 kcal of heat enters 1.38 kg of the following, originally at 30.2°C. The specific heat capacity for each material is given in square brackets below. (a) water [1.00 kcal/(kg · °C)] °C (b) concrete [0.20 kcal/(kg · °C)] °C (c) steel [0.108 kcal/(kg · °C)] °C (d) mercury [0.0333 kcal/(kg · °C)] °C

The same amount of heat entering identical masses of different substances produces different temperature changes. Calculate the final temperature when 1.40 kcal of heat enters 1.83 kg of the following, originally at 28.2°C. The specific heat capacity for each material is given in square brackets below. (a) water [1.00 kcal/(kg · °C)] °C (b) concrete [0.20 kcal/(kg · °C)] °C (c) steel [0.108 kcal/(kg · °C)] °C (d) mercury [0.0333 kcal/(kg · °C)] °C

A cube of ice is taken from the freezer at -9.5 °C and placed in a 95-g aluminum calorimeter filled with 300 g of water at room temperature of 20.0 °C. The final situation is observed to be all water at 16.0 °C. The specific heat of ice is 2100 J/kg · C°, the specific heat of aluminum is 900 J/kg · C°, the specific heat of water is is 4186 J/kg·C°, the heat of fusion of water is 333 kJ/Kg. Part A What was the mass of the ice cube? Express your answer to two significant figures and include the appropriate units. ? Value Units m = Submit Request Answer

What is the ratio of the energy required to warm 125 g of Ice (0.0 \deg C) to body temperature (37 \deg C) to warming the same amount of water through the same temperature change? Answer format is the number Eice/Ewater = (2 significant figures) Latent Heat of Fusion of Water: 335, 000 J/kg Specific Heat Capacity of Water: 4186 J/kg/\deg C

In an insulated vessel, 239 g of ice at 0°C is added to 635 g of water at 15.0°C. (Assume the latent heat of fusion of the water is 3.33 x 10° J/kg and the specific heat is 4,186 J/kg · °C.) (a) What is the final temperature of the system? °C (b) How much ice remains when the system reaches equilibrium?