How much heat is released when 105 g of steam at 100.0 C is cooled to ice at -15.0 C? The enthalpy of vaporization of water is 40.67 kj/mol, the enthalpy of fusion for water is 6.01 kj/mol, the specific heat capacity of liquid water is 4.18 J/g C and the specific heat capacity of ice is 2.02 J/g C. (q heating = m x C x ΔT, q phase change = ΔH vap x n)
How much heat is released when 105 g of steam at 100.0 C is cooled to ice at -15.0 C? The enthalpy of vaporization of water is 40.67 kj/mol, the enthalpy of fusion for water is 6.01 kj/mol, the specific heat capacity of liquid water is 4.18 J/g C and the specific heat capacity of ice is 2.02 J/g C. (q heating = m x C x ΔT, q phase change = ΔH vap x n)
Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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How much heat is released when 105 g of steam at 100.0 C is cooled to ice at -15.0 C? The enthalpy
of vaporization of water is 40.67 kj/mol, the enthalpy of fusion for water is 6.01 kj/mol, the specific heat
capacity of liquid water is 4.18 J/g C and the specific heat capacity of ice is 2.02 J/g C.
(q heating = m x C x ΔT, q phase change = ΔH vap x n)
of vaporization of water is 40.67 kj/mol, the enthalpy of fusion for water is 6.01 kj/mol, the specific heat
capacity of liquid water is 4.18 J/g C and the specific heat capacity of ice is 2.02 J/g C.
(q heating = m x C x ΔT, q phase change = ΔH vap x n)
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Step 1: Heat required to convert 100°C steam to 100°C liquid water
VIEWStep 2: Heat required to convert 100°C liquid water to 0°C liquid water
VIEWStep 3: Heat required to convert 0°C liquid water to 0°C ice
VIEWStep 4: Heat required to convert 0°C ice to -15°C ice
VIEWStep 5: Total heat required
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