How many moles of lithium hydroxide would be required to produce 26.0 g of Li₂CO3 in the following chemical reaction? 2 LiOH(s) + CO₂(g) - > Li₂ CO3(s)+ H₂O(l)

Solid copper can be produced by passing gaseous ammonia over solid copper (II) oxide at high temperatures, according to the following reaction.   NH3 (g) + CuO (s) → N2 (g) + Cu (s) + H2O (g)  Balance the reaction.

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Hello, I need help understanding how to properly balance this equation.

1)isothermic,exothermic, or endothermic 2)combustion,descombotion,synthesis,acid-base,double replacement,or single replacement

Sodium hydrogen carbonate (NaHCO3), also known as sodium bicarbonate or "baking soda", can be used to relieve acid indigestion. Acid indigestion is the burning sensation you get in your stomach when it contains too much hydrochloric acid (HCI), which the stomach secretes to help digest food. Drinking a glass of water containing dissolved NaHCO, neutralizes excess HCI through this reaction: HCl(aq) + NaHCO3(aq) NaCl(aq) + H₂O(1) + CO₂(g) The CO₂ gas produced is what makes you burp after drinking the solution. Suppose the fluid in the stomach of a man suffering from indigestion can be considered to be 200 ml of a 0.050 M HCI solution. What mass of NaHCO, would he need to ingest to neutralize this much HCI? Be sure your answer has the correct number of significant digits. X

The reaction for producing glucose in plants, called photosynthesis, is   6CO2+6H2O−→−−lightC6H12O6+6O2 6CO2+6H2O→lightC6H12O6+6O2    If a plant produces 7.56 mol C6H12O6,7.56 mol C6H12O6, how many moles of CO2CO2 are needed?

Fe(no3)3 (aq)+3NaOH(aq) Fe(OH)3(s)+ 3NaNo3(aq) how many moles of NaOH would be required to produce 0.40 moles of Fe(OH)3?

= (1) H H H H (2) (3)

For each reaction in the table below, write the chemical formulae of any reactants that will be oxidized in the second column of the table. Write the chemical formulae of any reactants that will be reduced in the third column. reactants oxidized reactants reaction reduced Ni(s) + I, 6) Nil, (5) SCr(s) + S;(5) – 8Crs (s) Cr(s) + 2C1, (3) – CrCı, (;)