How many inches of 1/8-in weld are necessary to transfer a shear force of 6000 lb from one plate to another? Assume that Fv = 13,600 lb/in2.
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How many inches of 1/8-in weld are necessary to transfer a shear force of 6000 lb from one plate to another? Assume that Fv = 13,600 lb/in2.
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- The allowable unit stress in shear on a fillet weld is 15,000 psi, and the total actual length of the weld CANNOT exceed 3in. If the weld must transmit a total force equal to 9600 lb, it's size should be A. 1/2 in. B. 3/8 in. C. 5/16 in. D. 1/4 in.A 100 x 100 x 10 mm angle is to be welded to a gusset plate. The angle carries a load of 200 kN applied along its centroidal axis which is 28.7 mm above the short leg as shown in the figure. Use an 8 mm fillet weld with a minimum tensile strength Fu = 483.33 MPa. Determine the length of a transverse fillet weld along the edge of the angle in order to avoid eccentricity of loading. Determine the length of side fillet weld required at the heel. Determine the length of side fillet weld required at the toe.1. Refer to the sketch below. a. What type of joint is shown? b. What type of weld is shown? C. Is the weld in shear or normal stress? d. Calculate the magnitude of stress in the weld. K /P= 50 Kip /P = 50 Kip 10" I 1/4"
- 2. Determine the lengths of the side fillet welds required at the heel and toe of the angle shown. Allowable shearing stress through the throat of each weld is 124 MPa. L 150 x 150 x 13 L1 P1 108 13 150 mm T= 250 kN P21 L2 gusset plate 150* A 76 mm x 76mm x 6mm angular section is welded to a gusset plate having a thickness of 8mm as shown in the figure. The length L1 equals 125mm and L2 is 65mm. The angular section has a cross sectional area of 929mm2, Fy=248 MPa, Fu=400MPa. Determine the value of tensile force P based on block shear in gusset plate along the weld in kN. Allowable stresses: Allowable tensile stress (gross area) = 0.6Fy Allowable tensile stress (net area) = 0.50Fu Allowable shear stress (net area) = 0.30Fu P gusset plate L₂= 65 mm 25 mmDetermine the shear Load that act on the fillet weld that joining two plates together if the working stress is 11300 Ib/in? Throat
- The vertical member shown in Figure STCN17.02 consist of two angles welded to the 8-mm thick gusset plate. Given the following data: Angle size: 75 mm x 50 mm x 6 mm (long legs back-to-back) Area of one angle = 738 mm Size of weld = 6 mm Yield strength of steel, Fy = 248 MPa Allowable weld shear stress, F, = 124 MPa a = 25 mm a. Determine the safe capacity of the vertical member in kN. b. If P= 185 kN, determine the length of weld L2 (mm) such that each weld have equal shear stress. Neglect end returns. c. If L1 = 140 mm and L2 = 70 mm, determine the safe load P (kN) based on weld capacity assuming all welds have equal stress. AP L1 L2Compute the size of fillet weld for a bracket connection with ISMB 300 column as shown in figure. Permissible shear stress in weld = 110 MPa. %3D 425 mm 100 kN 300 Single 12 mm plate 250 mmDetermine the maximum effective net area of the fillet weld using the maximum weld allowed by the code. Length of 550 mm and a maximum weld size is 12.5 mm. * P 10,601 sq.mm. 9721 sq.mm. 8840 sq.mm. O 1100 sq.mm.
- Regardless of the design load, the effective length of a 5/8 in. fillet weld that is subjected to stress in a longitudinal direction should not not be less than A. 2 in. B. 2 1/2 in. C. 3 in. D. 3 1/2 in.The allowable unit stress in shear on a fillet weld is 13,600 psi, and the total actual length of the weld CANNOT exceed 3 in. If the weld must transmit a total force equal 9600 lbs, its size should beUse an elastic analysis and determine the maximum load per inch of weld.