How many elements are in the set {1,{1}, {1,{1}}} ? Explain.

def remove_after_kth(items, k=1): Given a list of items, some of which may be duplicated, create and return a new list that is otherwise the same as items, but only up to k occurrences of each element are kept, and all occurrences of that element after those first k are discarded. Hint: loop through the items, maintaining a dictionary that remembers how many times you have already seen each element. Update this count as you go, and append each element to the resultlist only if its count is still at most equal to k. items k expected results [42, 42, 42, 42, 42, 42, 42] 3 [42, 42, 42] ['tom', 42, 'bob', 'bob', 99, 'bob', 'tom', 'tom', 99] 2 ['tom', 42, 'bob', 'bob', 99, 'tom', 99] [1, 2, 3, 4, 5, 4, 3, 2, 1, 2, 3, 4, 5, 4, 3, 2, 1] 1 [1, 2, 3, 4, 5] [1, 2, 3, 4, 5, 4, 3, 2, 1, 2, 3, 4, 5, 4, 3, 2, 1, 2, 3, 4, 5] 3 [1, 2, 3, 4, 5, 4, 3, 2, 1, 2, 3, 4, 5, 1, 5] [42, 42, 42, 99, 99, 17] 0 [ ] Please add comments between the codes so I can understand

Write the Java code for the merge part of the merge sort.

write down all elements in set notation.

Why is it very important to know how the GROUPING SETS phrase works?

What is the worstSpace(n) of Radix Sort?

int [] myArray = {2,3,4,5}: What is the length of myArray? type your answer.

enter the answer in set notation.

First Pass: ( 5 1 4 2 8 ) \to ( 1 5 4 2 8 ), Here, algorithm compares the first two elements, and swaps them. ( 1 5 4 2 8 ) \to ( 1 4 5 2 8 ), Swap since 5 > 4 ( 1 4 5 2 8 ) \to ( 1 4 2 5 8 ), Swap since 5 > 2 ( 1 4 2 5 8 ) \to ( 1 4 2 5 8 ), Now, since these elements are already in order (8 > 5), algorithm does not swap them. Second Pass: ( 1 4 2 5 8 ) \to ( 1 4 2 5 8 ) ( 1 4 2 5 8 ) \to ( 1 2 4 5 8 ), Swap since 4 > 2 ( 1 2 4 5 8 ) \to ( 1 2 4 5 8 ) ( 1 2 4 5 8 ) \to ( 1 2 4 5 8 ) Now, the array is already sorted, but our algorithm does not know if it is completed. The algorithm needs one whole pass without any swap to know it is sorted. Third Pass: ( 1 2 4 5 8 ) \to ( 1 2 4 5 8 ) ( 1 2 4 5 8 ) \to ( 1 2 4 5 8 ) ( 1 2 4 5 8 ) \to ( 1 2 4 5 8 ) ( 1 2 4 5 8 ) \to ( 1 2 4 5 8 ) Finally, the array is sorted, and the algorithm can terminate. Bubble sort is a simple sorting algorithm. It works by repeatedly stepping through the list to be sorted, comparing each pair of…

numpy array (([[-13,-38,22,-41,25], [-45,29,14,-34,-49], [26,21,-44,-25,0], [-30,-32,34,-39,-22], [-21,-36,0,18,37], [37,44,46,36,-37]]) Use indexing to extract the following slicers from the array [14,-34,-49], [-44,-25,0], [34,-39,-22] [[-30,-32,34,-39,-22], [-45,29,14,-34,-49], [-21,-36,0,18,37]] [25,34,46,-36]