How many address bits are needed for a word size of 1024K?

For a 512k x 32-bit memory system, what is the capacity in bytes? Give the exact number. Remember that 512k is shorthand for 524,288. 16,777,216 16,384,000 2,048,000 2,097,152

Consider a system with a cell size of 128 bits that needs to be able to address 103 MB of memory. What is the minimum number of address lines it must have?

Consider two possible floating point storage formats: Format 1 Format 2 • 16 bits total 32 bits total 1 bit for the number sign 1 bit for the number sign o 7 bits for the signed 23 bits for the signed exponent exponent O 8 bits for the mantissa O 8 bits for the mantissa Which format has the smaller maximum relative round-off error for a single calculation? • Format 2 It is impossible to tell Format 1 They are the same