Biochemistry
9th Edition
ISBN: 9781319114671
Author: Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher: W. H. Freeman
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- Why is the net charge 0 for cooh? Shouldn't it be +1?arrow_forwardIs B monomer a beta fructose or alpha fructose. How do you know?arrow_forwardModify isoleucine to show the predominant forms at pH 1, 7, and 13. Isoleucine has, values of 2.4 (carboxyl group) and 9.7 (amino group). Isoleucine at pH 7 Isoleucine at pH 1 CH3 CH₂ + H₂C CH +H₂N- C H Incorrect Isoleucine at pH 13 Incorrect H₂C H₂N- CH₂ | CH₂ CH c- C H 0 ĭ Incorrect H₂C +H₂N-arrow_forward
- What type of bond is created to form maltose? What is the waste product? * Maltose consists of two molecules of glucose that are linked by an a-(1,4') glycosidi (5 d.arrow_forwardShow anabolism of two molecules of serine. Be sure to clearly identify each molecule and bond/linkage involved. Hand-draw the diagramarrow_forwardConsider the positively charged amino acid lysine Lys2+ 21 COOH I H&N-C-H I pH 14 12 10 8 6 4 2 0 CH₂ I CH₂ I CH₂ I CH₂ T NH₂+ 0 Nelson p85 2.18 = 2.18 PK₁ Lys+ COO™ I H₂N-C-H H₂N-C-H ī I -----) 8.95 Lysº 8.95 pK₂ pka carboxyl = 2.19 pkaamino = 9.67 pka sidechain = 4.25 COO™ I CH₂ I CH₂ I CH₂ I CH₂ I NH₂¹ 1.0 2.0 Equivalents of OH added- COO™ I H₂N-C-H I 10.79 1 10.79 pk Isoelectric point Lys CH₂2 I CH₂ I CH₂ I CH₂ T NH₂ 3.0 +H3N NH3+ T CH₂ T CH₂ CH₂ CH₂ -COO™ H Lysine (Lys, K) Physiological pH = 7.4 < pl → Amino acid is positively charged at physiological pH 1. Consider glutamate in its fully protonated form (e.g. in a pH = 1 solution) 1) Draw all the forms of glutamate at various pH 2) Calculate the pl of this amino acid 3) Sketch a titration curve showing pH as a function of added [OH-] and locate the predominant forms of histidine in the curve STEPS: 1. Find the H atoms that can be removed on the molecule 2. Associated a pka value to each removable H. 3. Draw the Aa structure at:…arrow_forward
- 1arrow_forwardIdentify and encircle the peptide bonds in this polypeptide (Asp-Sec-Leu-Cys-Glu).arrow_forwardLefer to the figure showing the molecular structure of dimethylmercury. H–C-Hg C-H H. Exposure of human skin to a single drop of dimethylmercury can lead to death, as it is highly poisonous and passes easily cell membranes. Based on its structure, why is it able to pass so easily through cell membranes? I-0-I IICIHarrow_forward
- The φ angle represents rotation about which bonds? (mark these bonds with a φ directly on this structure)arrow_forwardDraw the oligopeptides' structure and provide the corresponding name for each oligopeptide 1. Dipeptide Ala-His 2. Tripeptide Glu-Pro-Cys Note: First residue is the N-terminal amino acidarrow_forwardIdentify the following amino acids and their following side chain.arrow_forward
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