he parallel plates of an air capacitor are separated by 3.25 mm. Each plate carries a charge of 6.50 nC. The magnitude of the electric field of the plates is 4.75 X 105 V/m. Find the (a) potential difference between the plates, (b) capacitance, and (c) area of a plate.

Consider a parallel-plate capacitor whose (circular) plates are separated by a 3.0-mm-thick slab of glass with dielectric constant 5.0. The diameter of each plate is 4.0 cm, and the slab fills the entire volume between the plates. The electric field between the plates with the dielectric in place has magnitude 8.0 x 103 V/m. (a) Find the magnitude of the charge on either plate of the capacitor. (b) Now suppose the slab of glass is removed, leaving an air gap between the plates. Calculate the total energy stored in this capacitor and the energy density (energy per unit volume).

An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated by a distance of 2.20 mm. (a) If a 15.0 V potential difference is applied to these plates, calculate the electric field between the plates. 33 Your response differs from the correct answer by more than 100%. kV/m (b) What is the surface charge density? 80.45 Your response differs from the correct answer by more than 10%. Double check your calculations. nC/m² (c) What is the capacitance? 3.1 pF .(d) Find the charge on each plate. Enter a number. differs from the correct answer by more than 10%. Double check your calculations. pC

An air-filled parallel-plate capacitor has plates of area 2.00 cm2 separated by 1.80 mm. The capacitor is connected to a(n) 21.0 V battery. (a) Find the value of its capacitance. pF (b) What is the charge on the capacitor? pC (c) What is the magnitude of the uniform electric field between the plates? N/C