M-(1zy.z– Iy.y) + M,(1,.z – Izy-y)Iz ly – IzyPrMyFormüller; o =--to - a0p + of < ož ,Oz + ØyCortPr• 02-Imaks =2t2Ox + ØyTe d?y _M(x)I dr?Omaks.min+ Ty, E = aAT, 1 =-.EI+ Tảy tc/pMalanıcpxc, @p/c =EIMalanıpeElTmaks =238 mmdx. PærVQyMP AIt38 mm diameter AB shaft, Oakma = 250 MPa Made of a strong steel.Using the maximum shear stress criterion, find the maximum torqueT so that no yielding occurs when P = 240 kN.899,025 Nm717,015 Nm799,025 Nm817,115 Nm617,125 Nm

given data load P= 240kN allowable stress = 250 MPa required = torque

Answered: he maximum shear stress criteric at no…

Engineering

Mechanical Engineering

he maximum shear stress criteric at no yielding occurs when P = 24

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Question

M-(1zy.z– Iy.y) + M,(1,.z – Izy-y)
Iz ly – Izy
Pr
My
Formüller; o =--
t
o - a0p + of < ož ,
Oz + Øy
Cort
Pr
• 02-
Imaks =
2t
2
Ox + Øy
Te d?y _M(x)
I dr?
Omaks.min
+ Ty, E = aAT, 1 =-.
EI
+ Tảy tc/p
Malanıcpxc, @p/c =
EI
Malanıpe
El
Tmaks =
2
38 mm
dx. Pær
VQ
y
M
P A
It
38 mm diameter AB shaft, Oakma = 250 MPa Made of a strong steel.
Using the maximum shear stress criterion, find the maximum torque
T so that no yielding occurs when P = 240 kN.
899,025 Nm
717,015 Nm
799,025 Nm
817,115 Nm
617,125 Nm

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