A shaft composed of segments AC, CD, and DB is fastened to rigid supports and loaded as shown below. For bronze, aluminum, and steel the G, modulus of rigidity are 35 GPa, 28 GPA, and 83 GPa respectively. Determine the maximum shearing stress (in MPa) developed in each segment. Hint: EOIB =0 rotation of Brelative to AL0B =0 rotation of B relative to A Tools: J = D* T = D³t TL .. derive t JG 16 Hint: = 0 rotation of B relative to A T. = 500 N-m Tp = 800 N-m C Aluminum A Bronze Steel 25 mm 25 mm o 50 mm 2 m 2 m 2.5 m

A shaft composed of segments AC, CD, and DB is fastened to rigid supports and loaded as shown below. For bronze, aluminum, and steel the G, modulus of rigidity are 35 GPa, 28 GPA, and 83 GPa respectively. Determine the maximum shearing stress (in MPa) developed in each segment. Hint: EOIB =0 rotation of Brelative to AL0B =0 rotation of B relative to A Tools: J = D* T = D³t TL .. derive t JG 16 Hint: = 0 rotation of B relative to A T. = 500 N-m Tp = 800 N-m C Aluminum A Bronze Steel 25 mm 25 mm o 50 mm 2 m 2 m 2.5 m

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter8: Applications Of Plane Stress (pressure Vessels, Beams, And Combined Loadings)

Section: Chapter Questions

Problem 8.3.10P: Solve the preceding problem if F =90 mm, F = 42 kN, and t = 40°MPa

See similar textbooks

Similar questions

2. For the assembly shown, W = 6 kN. Determine the shearing stress of the bronze spring and steel spring in MPa. Note: Show FBD's and Deformation Illustrations. Bronze n=15 d= 15mm Steel D= 150mm n=10 G= 35GPA d= 10mm D= 100mm 1m G=83GPA 2.5 m 1.5 m W
A solid brass shaft is loaded as shown below by two torques TB- segments are LAB = 700 mm and LBC 600 mm. A dBc = dAB mm LAB mm B Com dBC For brass, G = 41 GPa. Neglect the effect of any stress concentrations. LBC Determine the smallest diameters dAB and dBC for which an allowable shear stress of 50 MPa is not exceeded. Express each diameter as an integer in units of mm. dAB To 1100 Nm and Tc = 300 Nm. The lengths of the two Determine the magnitude of the total angle of twist in the shaft caused by the two applied torques for the diameters found previously Express your result in units of radians with five decimal places of accuracy. PAC = rad
Bearing stress 4. Please provide proper discussion and illustration also complete solution and clear solution please thank you Determine the length of a square key to be used for a 3.73 kW, 1800 rpm electric motor if the motor shaft diameter is 35 mm and the width of the key is approximately one-fourth of the shaft diameter. The allowable shearing stress on the key is 2.45 MPa
A mild steel shaft transmits 'P' kW at 'N' r.p.m. It carries a central load of 900 N and is simply supported between the bearings 2.5 metres apart. Determine the size of the shaft, if the allowable shear stress is 42 MPa and the maximum tensile or compressive stress is not to exceed 56 MPa..Power (P) 22 in kW , Speed (N) 550 in Rpm
If the internal torque experienced by a hollow brass shaft (G = 39 GPa) at a section with diameter d = 100 mm with 3 mm thick walls is T = 12 kNm, which of the following is closest to %3D the magnitude of the minimum shear stress developed on that section? Select one: O A. 262 MPa O B. 501 MPa O C. 279 MPa O D. 533 MPa
1. A solid bar of circular cross section has a diameter of 40mm and length of 1300mm. G=80GPa and torque applied at both ends is 340 N.m. Determine the maximum shear stress in MPa. I need the answer asap pls
Q1: The shaft BC is hollow with inner and outer diameters of 100 mm and 120 mm respectively. Shaft AB and CD are solid and of diameter d. For the loading shown determine the maximum and minimum shear stress in shaft BC. 0.9 m 0.7 m d 0.5 m A 120 mm T = 10 kN.m i В TB = = 20 KN.m 1 C D Tc = 30 KN.mi Tp = 6 kN - m Figure Question1
100 kip 10 kip -ft The 4-in. diameter shaft shown above is made from a ductile brass alloy. Which of the following are closest to the principal stresses in the shaft? O01 = 31.8 ksi 02 = 76.4 ksi O 01 = 94.0 ksi 02=-62.1 ksi O 01 = 14.3 ksi %3D 02 = -6.37 ksi O o1 = 7.96 ksi !! 02 = 9.55 ksi
Q2:The composite torsion member as shown in Fig. If the allowable stresses for steel and aluminium are 84 Mpa and 70 Mpa respectively and if the composite shaft is not to twist more than 1.45°, determine the maximum torque T that can be applied to the member. Gs = 84 Gpa, Ga 28 Gpa. Aluminium Steel 75 .mm 100 mm 1m
100 kip 10 kip ft The 4-in. diameter shaft shown above is made from a ductile brass alloy. Which of the following are closest to the principal stresses in the shaft? 01 = 31.8 ksi 02 = 76.4 ksi = 94.0 ksi 02 = -62.1 ksi O0g - 14.3 ksi 02 = -6.37 ksi Oo= 7.96 ksi 02 = 9.55 ksi
Q1/ The 15-mm diameter steel bolt is screwed tightly into a block at A. Suppose that the couple forces F causes the ends of the wrench to be displaced 3 mm, determine the maximum shear stress in the bolt. Assume that the wrench is rigid and modulus of rigidity of steel is 75 GPa. 150 mm 150 mm mni
03: A shaft carrying three loaded pulleys with stepped diameters as shown. The modulus of rigidity for the shaft is (G-28GPA) and the shaft segments have the same lengths 48N.m (AB-BC-CD-30Cm). Determinc the following: GON.m 144N,m 1- Maximum shearing stress in the shaft CD. 2- The angle of twist of the pulley A relative to B.