he left side of a balanced chemical equation is shown below K2Cr2O7 + 4 H2SO4 + 3 SeO2 → If 0.600 moles of K2Cr2O7, 2.800 moles of H2SO4 and 1.500 moles of SeO2 are brought together and allowed to react, then H2SO4 is the limiting reagent K2Cr2O7 is the limiting reagent there are 1.300 moles of H2SO4 in excess there are 0.100 moles of K2Cr2O7 in excess
he left side of a balanced chemical equation is shown below K2Cr2O7 + 4 H2SO4 + 3 SeO2 → If 0.600 moles of K2Cr2O7, 2.800 moles of H2SO4 and 1.500 moles of SeO2 are brought together and allowed to react, then H2SO4 is the limiting reagent K2Cr2O7 is the limiting reagent there are 1.300 moles of H2SO4 in excess there are 0.100 moles of K2Cr2O7 in excess
World of Chemistry, 3rd edition
3rd Edition
ISBN:9781133109655
Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
Chapter9: Chemical Quantities
Section: Chapter Questions
Problem 56A
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Question
The left side of a balanced chemical equation is shown below
K2Cr2O7 + 4 H2SO4 + 3 SeO2 →
If 0.600 moles of K2Cr2O7, 2.800 moles of H2SO4 and 1.500 moles of SeO2 are brought together and allowed to react, then
H2SO4 is the limiting reagent |
||
K2Cr2O7 is the limiting reagent |
||
there are 1.300 moles of H2SO4 in excess |
||
there are 0.100 moles of K2Cr2O7 in excess |
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