he code in is Matlab. This is what I have so far. I"m not sure what to do.  function [P] = permutations(n, k) % calculate the number of permutations P P = 1; if k > n P = NaN; else for i = 1:n P = P*i; end end

e. Problem 5. Devise a function that receives a string and computes how many asterisks are in the string with a recursive method. For instance, if the input is "Able was I ere ***Elba", the function should output 3. If the input is "Peanuts", the function should return 0. Approach: Let's assume the signature of our function is countAsterisks(s) where s is the input string. In the body of your function, check if s[0] is equal to an asterisk. If the string contains only a single character and it is an asterisk, return 1. If the string contains only a single character and it is not an asterisk, return 0. If the string is longer than one character, determine if the first character is an asterisk and count it if this is the case. Then, create a new string s1 that is the same as the input string s but without the first character. Recursively call countAsterisks (s1) and return the value returned from this recursive call, plus one (if there is an asterisk in s[0]). Also, writing any explicit…

Python: How do I create a recursive function asterisk with both recursive and base cases?   so for n=3, you would have below; *** ** *   code that I have:   for i in range(n): print("*",end="")

-Python- Write a function get_letter_grade, such that when given * a lab grade score and * a list of the grade cutoffsreturns the letter grade of that score.Note: Your function automatically returns A for the values that are >= to the first cutoff-value in the list, then A- for the second cutoff-value, B+ for the third and so on. The function returns None for anything that's below the score for B-. You test that get_letter_grade(97, [93, 90, 87, 83, 80]) correctly returns an A, and get_letter_grade(93, [97, 90, 87, 83, 80]) returns A-. DO NOT hard-code the cutoffs, since they can change! You can copy/paste the following template: def get_letter_grade(score, cutoffs):    if score ... :        return 'A'    ...:        return 'A-'    ...:        return 'B+'    ...:        return 'B'    ...:        return 'B-'

Write code to complete raise_to_power(). Note: This example is for practicing recursion; a non-recursive function, or using the built-in function math.pow(), would be more common.Sample output with inputs: 4 24^2 = 16 def raise_to_power(base_val, exponent_val):   if exponent_val == 0:      result_val = 1   else:      result_val = base_val * ''' Your solution goes here '''    return result_val user_base = int(input())user_exponent = int(input()) print('{}^{} = {}'.format(user_base, user_exponent,      raise_to_power(user_base, user_exponent)))

In loop functions.py, define a function named permutations that takes two paramters, n and r, in that order. This function returns the number of different permutations of length r from set of size n. Essentially to calculate these permutations, the function should compute the product (n - r+1)*(n-r+2)*(n-r+3)*...*(n-2)*(n-1) or n!/(n-r)!. No if statements or built in math functions should be used. For or while loops are best reccomended.

Write code to complete raise_to_power(). Note: This example is for practicing recursion; a non-recursive function, or using the built-in function math.pow(), would be more common.Sample output with inputs: 4 24^2 = 16     def raise_to_power(base_val, exponent_val):   if exponent_val == 0:      result_val = 1   else:      result_val = base_val *   Your solution goes here    return result_val user_base = int(input())user_exponent = int(input()) print('%d^%d = %d' % (user_base, user_exponent,      raise_to_power(user_base, user_exponent)))