the answer in M1 is 4283.29lb, can you show me how to get this answer? 093 M2 - D815 M3 =0> 0.093 M2 +o.81S M3=0From egn (ii) andCiv);M2= Z€3t 2036-77lb%3DM3 = -232.92bFBD of 400lb blockJaTn400lbfiM,ŹFy =0(1)M, -400 – M2 cos (is)-f28im (15)-0M-400-2036-千子 cwis)-0-364×036.47sinlis)-o> M, =4283.29 IbS Fx -0(->)-P-M2Sin15)+f2ws(15)+ fi =0O 364 x4283.29 + 0-364x 2036.77coS CIS)-2036-7 Sun (15)PP = 1748.0sbforo P im moving:. The fhonizontal folefttotheP- 1748 -os lb (b) When 400 lb s movngdeft :FBDfor 2000 lb lock;2000lbM3fzM2E Fy =0 (1)M2 cos (1s)+f2 sin (i5)- 2000+ M2 cos(70)+ fz Sm (70) =0M2 cos (1s) 40:364 Mz sino(is)+ M3 cos(70)+o364 M3 sin(70) = 20001.06 M2 + 0.684 M3 = 2000-E Fx =0 (>)M2simcis)-f2wslis)- M2 sinl70)+ f3 Cos (70)%3DM28 im(is)-0.364 Mq cos(is)-M3 sio()+0 364 Mg oS(70) =0.

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Answered: he answer in M1 is 4283.29lb, can you…

Engineering

Mechanical Engineering

he answer in M1 is 4283.29lb, can you show me how to get this answer

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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the answer in M₁ is 4283.29lb, can you show me how to get this answer?

093 M2 - D815 M3 =0
> 0.093 M2 +o.81S M3=0
From egn (ii) and
Civ);
M2= Z€3t 2036-77lb
%3D
M3 = -232.92b
FBD of 400lb block
Ja
Tn
400lb
fi
M,
ŹFy =0(1)
M, -400 – M2 cos (is)-f28im (15)-0
M-400-2036-千子 cwis)-0-364×036.47
sinlis)-o
> M, =4283.29 Ib
S Fx -0(->)
-P-M2Sin15)+f2ws(15)+ fi =0
O 364 x4283.29 + 0-364x 2036.77
coS CIS)-2036-7 Sun (15)
P
P = 1748.0sb
foro P im moving
:. The fhonizontal fo
left
to
the
P- 1748 -os lb

(b) When 400 lb s movng
deft :
FBD
for 2000 lb lock;
2000lb
M3
fz
M2
E Fy =0 (1)
M2 cos (1s)+f2 sin (i5)- 2000+ M2 cos(70)
+ fz Sm (70) =0
M2 cos (1s) 40:364 Mz sino(is)+ M3 cos(70)
+o364 M3 sin(70) = 2000
1.06 M2 + 0.684 M3 = 2000-
E Fx =0 (>)
M2simcis)-f2wslis)- M2 sinl70)+ f3 Cos (70)
%3D
M28 im(is)-0.364 Mq cos(is)-M3 sio()
+0 364 Mg oS(70) =0.

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