have to be to get a margin of error less than 0.02 for p?

Q: X~N(40,?2) and P(X>50) = 0.119. Find the value of ?.

A: From the provided information, Mean (µ) = 40 Variance = σ2 X~N (40, σ2)

Q: The formula for z-test for proportion is: ?=p̂−????√z=p̂−ppqn Solve it for p̂. Please do not…

A: We know that,  Population proportion (p), sample size (n) and sample proportion (p̂)  Then,…

Q: (). 0.001 t3 + Ot + 2t-750n = 0 3

A: 0.0013t3+0· t+2t-750π=0⇒0.00033…t3+2t-2356.19449…=0By an online calculator,⇒t≈ 181.50539…

Q: Find P(2.03 < z < 4)=

A: To find : P(2.03 &lt; z &lt; 4) Here, Z is the standard normal variate.

Q: What is the value of P(z < -1.33)? Notes: 1. Write your answer using four decimal places (i.e.…

A: Given : Z be a standard normal variable Z~N(0,1)

Q: Assume P(Z>b)=0.22 for some number b. Without finding the value of b, what is P(Z<-b)?

A: From the provided information,P (Z&gt;b) = 0.22

Q: Calculate P (Z > -0.1). (Round to the hundredths).

A: We have to find given probability.

Q: What is P( -1.03 < Z < 0.57 )?

A: The question is about standard normal distribution Introduction : Standard normal distribution. Z is…

Q: Compute the indicated quantity. P(A | B) = 0.3, P(B) = 0.8. Find P(A n B). P(A n B) =

A: Using conditional probability we get:P(A|B)=0.3P(A∩B)P(B)=0.3P(A∩B)=0.3P(B)P(A∩B)=0.3×0.8 [given…

Q: P(Z > 0.98)=

A:

Q: Calculate P (Z < 0). (Round to the hundredths).

A: GivenP(Z≤0)=

Q: P(z< ( Or equal to ) z0) = 0.7054

A:

Q: 9/State the Sufficient condition for the best apfraximation ant Prove t

A:

Q: Given, P(A or B) = 0.80, P(B') = 0.33 and P(A and B) = 0.20 Find P(A' and B)?

A: Solution-: P(A or B)=0.80, P(B')=0.33 and P(A and B)=0.20 We wan to find P(A' and B)=?

Q: P(z < 2.56) =

A: Draw the graph that represents the area to the left of the normal curve.

Q: Assume P(Z> b) = 0.35 for some number b. Without finding the value of b, what P(Z < – b)?

A:

Q: Lydia wonders if all bag of candy she got were the same size, so she opens them and counts how many…

A: There are total 5 bags.

Q: for d how can you calculate  the p value without excel?  need to be able to do on a test without…

A: Given  Given information: n=25 Sample size  Sample mean  x¯= 6.3  Sample standard deviation  s = 1.8

Q: find p (z<0.92) refer to the table of x-scores

A: p (z&lt;0.92) =?

Q: Determine  for n=10 and r=0.50. What is p(x=8)

A:

Q: The Flesch Reading Ease Test is a test that ranks the reading level of passages. But WB for the…

A: Given formula for the score F of fetch test is F=206.835-1.015WS-84.6LW                 (i) Where…

Q: Use T7(x; 2) to approximate In (0.9). Round to 4 decimal places.

A: The given function is fx=ln3-x.   The Taylor polynomial of degree 2 for a function fx at  point x=a…

Q: P(1.15 < Z < 2.77) =

A: X~N( 0 , 1 )   μ=0 , ?=1 (for standard normal distribution)   Z-score =( x - μ )/?

Q: for f(2,54) = 6.10, p >.01, what is the value of the df totoal

A: Solution Given  f(2,54) = 6.10, p &gt;.01,

Q: follow until degrees of freedom becomes p-value. How did we get to 0.0036?

A:

Q: n=10,p=0.3,x<4

A: The formula for binomial probability is represented as :   Given: n=10 p=0.3 x&lt; 4

Q: Find P(1.73< Z < 2.16)

A:

Q: Find P (-0. 55 < z < 2.51)

A:

Q: for f(3,46) = 6.10, p >.01, how many levels of the independant variables were there

A: Solution f(3,46) = 6.10, p &gt;.01,

Q: Compute the indicated quantity. P(A|B) = 0.5, P(An B) = 0.4. Find P(B). P(B) Enter a number.

A: According to the given information, we have P(A|B) = 0.5P(A∩B)=0.4

Q: P(Z < 0.58) = %3D 0. J0.2 J0.8 0.28 0.72

A: Given that, P(Z&lt;0.58)

Q: Let X represent the difference between the number of heads and the number of tails when a coin is…

A: Given that: Total number of times a coin tossed, n=36 To find: Probability of getting the difference…

Q: Round to the fourth a) Find P(Z<-3.3)=

A: Solution-: We find, P(Z&lt;-3.3)=?

Q: Find P (1.23 <z <2.35)

A:

Q: Find P (-2.15 <Z<1.63)

A: Given:  z be the standard normal variate then to find probability p(-2.15&lt;z&lt;1.63)??

Q: If n=10 and p=0.7, find P(x=8)

A: