P(1.15 < Z < 2.77) =

Q: 1. P(0<z<1.44) 2. P(-2.81 <z<0).

A: 1)P(0&lt;z&lt;1.44)

Q: Find z given that P(.24 <Z <z) = .12

A:

Q: p(z < 1.29)

A: standard normal distribution Z~N(0,1) P(z&lt;1.29) = ?

Q: 1. a) Find the mean value u of the function f (x) = |3x| +3 on the interval [-2, 1] . %3!

A:

Q: Find P(-1.40 < Z < 0)     .4192     .1259     .4357     .8907

A: Solution: Let Z be the standard normal random variable with mean μ=0 and standard deviation σ=1…

Q: X~N(1.8, 0.4).  Find P(0.9 < X < 2.3).  (Round to 3 decimal places.)

A:

Q: P(z>1.2)

A: Given problem Given that   P(z&gt;1.2)   Ans) P( z&gt;1.2 ) is, = 1 - P( z ≤ 1.2 )

Q: Evaluate the followings: (a) P (z<?)=0.0643 (b)Z.70 (c) P(-1.41<z<-1.12) (d)Z.15

A: Z is standard normal distribution

Q: P(Z<1.89) (less than or equal to)

A: Given that.   X~N( 0 , 1 )   μ=0  , ?=1 (for standard normal distribution)    Z-score =( x - μ )/?

Q: find P (Z > 1.21) = find P (Z < 1.60) = find P (0.59 < Z < 1.78) =

A: 1) P (Z &gt; 1.21) =?

Q: Find the value for z if P( Z > z ) = 0.7643.     0.63     -0.72     0.72     -0.63

A: Given that, P-value = 0.7643 Right tailed

Q: Calculate P(Z < 1.5)

A:

Q: If m rst = 164, what is m<RVT?

A:

Q: Let X - T(28). Find P40(x) (50th percentile of X)

A: The (100p)th percentile is the value xp of the distribution such that (100p)% of the distribution…

Q: P(x < 17.872)

A: Let's take the given  Sample size n=33 from a population, with mean=16 and standard deviation=8.4…

Q: Find P(X < 0.3)

A:

Q: Find two z values so that 53% of the middle area is bounded by them.

A:

Q: If x5 = 15.21 and the absolute error in x5 is 0.02, then the relative error % in x5 is %3D

A: For example, take a one litre bottle and and take a one litre water that is measure to be one litre,…

Q: Let X - T(25). Find P30(X) (30th percentile of X)

A: Solution: From the given information, X follows T distribution with degrees of freedom 25.

Q: P(z < -2.61)

A: Z score = -2.61 Left tailed test

Q: Calculate P(z<-1.2)

A: The z-score is standard normal variable with mean 0 and standard deviation 1.

Q: P (Z<1.8572)

A: Answer - Find   P (Z&lt;1.8572)

Q: P(0.51 ≤ Z ≤ 1.4) =

A: Draw the normal curve and shade the area between z=0.51 and z=1.4.

Q: Suppose that f (x) = (3/2)x2 for −1< x < 1. Determine the mean and standard deviation of X.

A:

Q: If Z~N(0,1), then what is Pr(-0.09 < Z < 2.54)? You can use Excel. Enter your answer as a decimal…

A: We have to find given probability

Q: P(−0.71 ≤ Z ≤ 1.34) =

A: Draw the normal curve and shade the area between z=-0.71 and z=1.34.

Q: Find P(Z<0.5) and show in graph.

A: We will find P(Z&lt;0.5)  By looking into z-table for one tailed

Q: If P(-a < z < a) = 0.4314, find a.

A: Given that, P(-a &lt; z &lt; a) = 0.4314  We to find the value of a

Q: Find the value for z if P( Z < z ) = 0.7298.     -0.74     -0.61     0.74     0.61

A: Given that, P-value = 0.7298 Left tailed

Q: p(0 < z < 1.30)= p(0 < z < 1.83)= p(1.30 < z < 1.83)=

A: Given that:Z is standard normal Distributed with i.e. mean µ =0 and standard deviation σ =1 By…

Q: P(X ≤ 1). n = 5, p = 0.6

A:

Q: P(Z is less than 1.15)= ✔ [Select] 0.75923 0.8675 0.87493 0.1157

A: Standardized z-score:   The standardized z-score represents the number of standard deviations the…

Q: Suppose that we have a signal X(t), of which its samples X follow a uniform PDF over the range…

A: Hi, since you have posted a question with multiple sub-parts, we will solve first three subparts for…

Q: Sunnoso that DI t M M 0.9968 What is a good estimate

A: Given that

Q: P(0.74<Z<2.11)

A: Let Z be the standard normal variable with parameters μ=0  and σ=1 The probability is,

Q: P(- c ≤ Z ≤ c)=0.9399

A: We have given that  P(- c ≤ Z ≤ c)=0.9399 From the given information we have to find the value of c