Homework Help is Here – Start Your Trial Now!
Science
Advanced Physics
harmonic motion: pendulum" experiment, the accepted, experimental and percent discrepancy is given in the attached images. Based on this, what's the conclusion of the experiment? "The purpose of this lab experiment is to prove that the period of the simple pendulum is independent of both the mass of the hanging object and the angle of displacement of the pendulum. The experimental value for acceleration due to gravity using the period of the pendulum is also calculated." Accepted value of g= 9.80m/s^2 Experimental value of g=10.04 m/s^2 Percent discrepancy= 2.39

harmonic motion: pendulum" experiment, the accepted, experimental and percent discrepancy is given in the attached images. Based on this, what's the conclusion of the experiment? "The purpose of this lab experiment is to prove that the period of the simple pendulum is independent of both the mass of the hanging object and the angle of displacement of the pendulum. The experimental value for acceleration due to gravity using the period of the pendulum is also calculated." Accepted value of g= 9.80m/s^2 Experimental value of g=10.04 m/s^2 Percent discrepancy= 2.39

icon
Related questions
Question

For the "harmonic motion: pendulum" experiment, the accepted, experimental and percent discrepancy is given in the attached images. Based on this, what's the conclusion of the experiment?

"The purpose of this lab experiment is to prove that the period of the simple pendulum is independent of both the mass of the hanging object and the angle of displacement of the pendulum. The experimental value for acceleration due to gravity using the period of the pendulum is also calculated."

Accepted value of g= 9.80m/s^2

Experimental value of g=10.04 m/s^2

Percent discrepancy= 2.39%

trial 40cm 60cm 80cm 100cm Length (cm) N cycles 0.405 0.591 0.792 0.990 30 25 25 20 t(sec) 38.23 38.76 44.65 35.59 T=t/N sec/cycles 1.27 1.55 1.786 1.98 T^2 (sec)^2 1.62 2.40 3.19 3.92
Transcribed Image Text:trial 40cm 60cm 80cm 100cm Length (cm) N cycles 0.405 0.591 0.792 0.990 30 25 25 20 t(sec) 38.23 38.76 44.65 35.59 T=t/N sec/cycles 1.27 1.55 1.786 1.98 T^2 (sec)^2 1.62 2.40 3.19 3.92
L(length)(m) T^2 0.405 0.591 0.792 0.99 T^2 4.5 4 3.5 3 2.5 2 1.5 1 0.5 0 0 1.62 2.40 3.19 3.92 0.2 T^2 vs. L y = 3.93x +0.0531 0.4 0.6 LENGTH (M) 0.8 1 1.2
Transcribed Image Text:L(length)(m) T^2 0.405 0.591 0.792 0.99 T^2 4.5 4 3.5 3 2.5 2 1.5 1 0.5 0 0 1.62 2.40 3.19 3.92 0.2 T^2 vs. L y = 3.93x +0.0531 0.4 0.6 LENGTH (M) 0.8 1 1.2
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 3 steps

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer