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A bar has length L = 2 m and mass m =20kg. The bar is hung at the ends A and B with two springs of elastic constant k₁ = 500N/m and k2 = 2 k₁. The two springs are attached to the ceiling. Calculate the distance x from extreme A to place a mass M = 100 kg so that the elongations of the springs are equal.

A bar has length L = 2 m and mass m =20kg. The bar is hung at the ends A and B with two springs of elastic constant k₁ = 500N/m and k2 = 2 k₁. The two springs are attached to the ceiling. Calculate the distance x from extreme A to place a mass M = 100 kg so that the elongations of the springs are equal.

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Answer Step-wise with detailed explantions Please Answer the following question step-wise with detailed explanations. Thanks in advance A bar has length L = 2 m and mass m = 20kg. The bar is hung at the ends A and B with two springs of elastic constant k₁ = 500N/m and k2 = 2 k₁. The two springs are attached to the ceiling. Calculate the distance x from extreme A to place a mass M = 100 kg so that the elongations of the springs are equal.
Transcribed Image Text:Answer Step-wise with detailed explantions Please Answer the following question step-wise with detailed explanations. Thanks in advance A bar has length L = 2 m and mass m = 20kg. The bar is hung at the ends A and B with two springs of elastic constant k₁ = 500N/m and k2 = 2 k₁. The two springs are attached to the ceiling. Calculate the distance x from extreme A to place a mass M = 100 kg so that the elongations of the springs are equal.
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