H 30° 20m A cannonball is fired from a castle with the trajectory as shown in the figure. The initial velocity components are 180 m/s (horizontal) and 66 m/s (vertical). The cannonſiall reaches maximum height at point H and then hits the ground target at point G. What is the height of point H from the ground without considering air resistance? a) O 222 m b) O 242 m Answe c) O 45,000 m d) O444 m e) O 464 m Review Later

question 9

Doha kicks the ball in a parabolic path. The ball leaves the player’s foot with a speed of 20 m/s, making an angle of 40 o with the horizontal. a) Calculate the maximum height of its trajectory  b) Determine its velocity as it hits the ground again. Air resistance is negligible. c) How far from Darshan does the soccer ball land?

The initial speed of a tennis ball is 57.5 m/s and the launch angle is ?i = 16°. Neglect air resistance.Question 1) What is the maximum height, h, of the tennis ball? in mQuestione 2) What is the range, R, of the tennis ball? in m info given: what angle results in the greatest height=90 For this 90° angle, the horizontal component of velocity is zero, so the initial velocity is completely in the vertical direction, resulting in greatest height Kato tries substituting ty,max for t, 0 for yi, and h for yf, and gets h =  vi2 sin2 ?i 2g   When ?i = 90°, sin2 ?i is maximum, so h is maximum what angle results in the maximum horizontal range=45°  I substituted 2vi sin ?i g into the expression for the horizontal component of velocity, (vi cos ?i)t, and got  R =  2vi2 sin ?i cos ?i g when ?i = 45°, 2?i = 90°, and sin 90° = 1, which is its maximum value.