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The initial speed of a tennis ball is 57.5 m/s and the launch angle is ?i = 16°. Neglect air resistance.
Question 1) What is the maximum height, h, of the tennis ball? in m
Questione 2) What is the range, R, of the tennis ball? in m
info given: what angle results in the greatest height=90 For this 90° angle, the horizontal component of velocity is zero, so the initial velocity is completely in the vertical direction, resulting in greatest height
Kato tries substituting ty,max for t, 0 for yi, and h for yf, and gets
h =
| vi2 sin2 ?i |
| 2g |
When ?i = 90°, sin2 ?i is maximum, so h is maximum
what angle results in the maximum horizontal range=45°
I substituted
| 2vi sin ?i |
| g |
R =
| 2vi2 sin ?i cos ?i |
| g |
when ?i = 45°, 2?i = 90°, and sin 90° = 1, which is its maximum value.
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