Elements Of Electromagnetics
7th Edition
ISBN: 9780190698614
Author: Sadiku, Matthew N. O.
Publisher: Oxford University Press
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Transcribed Image Text:0: (34 || 4 10:14
Gold has the Face-Centered Cubic
(FCC) crystal structure shown in the
figure below. The atomic radius of
Gold is r = 0.1442 nm at room
temperature (20°C).
Calculate the edge length “a" of the
unit cell
Select one:
a. 0.333
b. 0.408
c. 0.488
d. 0.612
e. None of these
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- Answer the following question with drawing the atom configurations of the plane or direction.What is the planar density for the (110) plane in a FCC structure?arrow_forward1. Many substances crystallize in a cubic structure. The unit cell for such crystals is a cube having an edge with a length equal to do. -Face diagonal a. What is the length, in terms of do, of the face diagonal, which runs diagonally across one face of the cube? (Hint: Use the Pythagorean theorem.) b. What is the length, again in terms of do. of the cube diagonal, which runs from one corner, through the center of the cube, to the opposite corner? (Hint: Make a right triangle having a face diagonal and an edge of the cube as its sides, with the hypotenuse equal to the cube diagonal, then use the Pythagorean theorem again.) 2. In an FCC structure, the centers of the atoms are found on the corners of the cubic unit cell and at the center of each face. The unit cell has an edge whose length is the distance from the center of one corner atom to the center of another corner atom on the same edge. The atoms on the diagonal of any face are touching. One of the faces of the unit cell is shown…arrow_forward3. Under what conditions, will the body centered tetragonal lattice become (a) a bcc structure? (b) an fcc structure?arrow_forward
- Copper has a cubic structure with a = 0.36151 nm. The atomic radius is 0.1278 nm. The densityis 8.93 g/cm3, and the atomic mass is 63.55 g/mol. Determine(a) the number of atoms in each unit cell; and(b) the packing factor in the unit cell.arrow_forwardSketch the planar cross section for the following planes in the FCC structure (label the edge lengths in terms of a and R) and calculate the planar densities for the three planes (do so in terms of both atoms/nm2 AND the dimensionless quantity): a. (001)b. (011)c. (111)arrow_forward1. It is often convenient to represent a fcc lattice as simple cubic, with a cubic primitive cell of side a and a four-point basis. (a) Show that the structural factor is then either 4 or 0 at all points of the simple cubic reciprocal lattice. (b) Show that when points with zero structural factor are removed, the remaining points of the reciprocal lattice makes up a bcc cubic lattice with conventional cell of side 4л/a. Why is this expected?arrow_forward
- Need help on thisarrow_forwardCopper is a typical face-centered-cubic metal. In its pure state, it has extremely high electrical conductivity. Oxygen in copper causes a major reduction of conductivity. To investigate this issue further, I want to you to tell me whether oxygen atoms substitute for copper atoms, or if they enter interstitial sites.arrow_forwardAnswer only 1arrow_forward
- Consider an fcc lattice with cube side length 1.2 Å. What are the planar densities of the (110) and (100) planes respectively (in units of 1020 atoms/m?): (This question has only one correct answer) O a. (100) = 2.08, (110) = 0.98 O b. (100) = 1.39, (110) = 0.98 O c. (100) = 1.39, (110) = 1.20 O d. (100) = 0.98, (110) = 1.39arrow_forward4. Figure out the indexes of the following lattice planes. (The arrows are the basic vectors of the lattice.) (a) (b) (c)arrow_forwardConsider a unit cell with lattice dimensions a, b, and c in the x-, y and z directions. Which of the following sets of Miller indices can represent a crystallographic plane with intercepts of b and (c/4) along the y- and z-axes respectively? (more than one answer is possible for this question. marks will only be awarded for the question if all the correct options are selected (i.e. 'all or nothing' marking scheme). a. b. C. d. (214) (421) (114) e. (412)arrow_forward
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