Biochemistry
Biochemistry
9th Edition
ISBN: 9781319114671
Author: Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher: W. H. Freeman
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Glucose 1-Phosphate → Glucose 6-Phosphate
Glucose 1-Phosphate → Glucose 6-Phosphate
• (AG = -1.7 kcal/mole, K. = 19)
• Is the reaction exergonic or
endergonic? Exergonic - gives off
1.7 kcal/mole.
Reaction to
Reaction to
equilibrium
equilibrium
100% Glucose
100% Glucose
1-phosphate
6-phosphate
95% Glucose 6-phosphate
5% Glucose 1-phosphate
If reaction begins with 20 moles Glucose 1-PO4,
how much Glucose 1-PO, and Glucose 6-PO is
present at Chemical Equilibrium?
• K. = [Products]/[Reactants]
• K=19, so will be 19 moles of Product (G 6-P)
for every 1 mole of Reactant (G 1-P)
Reaction to
Reaction to
equilibrium
equilibrium
100% Glucose
1-phosphate
100% Glucose
6-phosphate
95% Glucose 6-phosphate
5% Glucose 1-phosphate
expand button
Transcribed Image Text:Glucose 1-Phosphate → Glucose 6-Phosphate Glucose 1-Phosphate → Glucose 6-Phosphate • (AG = -1.7 kcal/mole, K. = 19) • Is the reaction exergonic or endergonic? Exergonic - gives off 1.7 kcal/mole. Reaction to Reaction to equilibrium equilibrium 100% Glucose 100% Glucose 1-phosphate 6-phosphate 95% Glucose 6-phosphate 5% Glucose 1-phosphate If reaction begins with 20 moles Glucose 1-PO4, how much Glucose 1-PO, and Glucose 6-PO is present at Chemical Equilibrium? • K. = [Products]/[Reactants] • K=19, so will be 19 moles of Product (G 6-P) for every 1 mole of Reactant (G 1-P) Reaction to Reaction to equilibrium equilibrium 100% Glucose 1-phosphate 100% Glucose 6-phosphate 95% Glucose 6-phosphate 5% Glucose 1-phosphate
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