Glucose 1-Phosphate → Glucose 6-Phosphate Glucose 1-Phosphate → Glucose 6-Phosphate • (AG = -1.7 kcal/mole, K. = 19) • Is the reaction exergonic or endergonic? Exergonic - gives off 1.7 kcal/mole. Reaction to Reaction to equilibrium equilibrium 100% Glucose 6-phosphate 100% Glucose 1-phosphate 95% Glucose 6-phosphate If reaction begins with 20 moles Glucose 1-PO4, how much Glucose 1-PO, and Glucose 6-PO, is present at Chemical Equilibrium? • K. = [Products]/[Reactants] • K=19, so will be 19 moles of Product (G 6-P) for every 1 mole of Reactant (G 1-P) Reaction to equilibrium Reaction to equilibrium 100% Glucose 100% Glucose 1-phosphate 6-phosphate 95% Glucose 6-phosphate 5% Glucose

Biochemistry
9th Edition
ISBN:9781319114671
Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Chapter1: Biochemistry: An Evolving Science
Section: Chapter Questions
Problem 1P
icon
Related questions
Question

 Can you explain this? The answers are in it but I don't understand

Glucose 1-Phosphate → Glucose 6-Phosphate
Glucose 1-Phosphate → Glucose 6-Phosphate
• (AG = -1.7 kcal/mole, K. = 19)
• Is the reaction exergonic or
endergonic? Exergonic - gives off
1.7 kcal/mole.
Reaction to
Reaction to
equilibrium
equilibrium
100% Glucose
100% Glucose
1-phosphate
6-phosphate
95% Glucose 6-phosphate
5% Glucose 1-phosphate
If reaction begins with 20 moles Glucose 1-PO4,
how much Glucose 1-PO, and Glucose 6-PO is
present at Chemical Equilibrium?
• K. = [Products]/[Reactants]
• K=19, so will be 19 moles of Product (G 6-P)
for every 1 mole of Reactant (G 1-P)
Reaction to
Reaction to
equilibrium
equilibrium
100% Glucose
1-phosphate
100% Glucose
6-phosphate
95% Glucose 6-phosphate
5% Glucose 1-phosphate
Transcribed Image Text:Glucose 1-Phosphate → Glucose 6-Phosphate Glucose 1-Phosphate → Glucose 6-Phosphate • (AG = -1.7 kcal/mole, K. = 19) • Is the reaction exergonic or endergonic? Exergonic - gives off 1.7 kcal/mole. Reaction to Reaction to equilibrium equilibrium 100% Glucose 100% Glucose 1-phosphate 6-phosphate 95% Glucose 6-phosphate 5% Glucose 1-phosphate If reaction begins with 20 moles Glucose 1-PO4, how much Glucose 1-PO, and Glucose 6-PO is present at Chemical Equilibrium? • K. = [Products]/[Reactants] • K=19, so will be 19 moles of Product (G 6-P) for every 1 mole of Reactant (G 1-P) Reaction to Reaction to equilibrium equilibrium 100% Glucose 1-phosphate 100% Glucose 6-phosphate 95% Glucose 6-phosphate 5% Glucose 1-phosphate
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps

Blurred answer
Recommended textbooks for you
Biochemistry
Biochemistry
Biochemistry
ISBN:
9781319114671
Author:
Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher:
W. H. Freeman
Lehninger Principles of Biochemistry
Lehninger Principles of Biochemistry
Biochemistry
ISBN:
9781464126116
Author:
David L. Nelson, Michael M. Cox
Publisher:
W. H. Freeman
Fundamentals of Biochemistry: Life at the Molecul…
Fundamentals of Biochemistry: Life at the Molecul…
Biochemistry
ISBN:
9781118918401
Author:
Donald Voet, Judith G. Voet, Charlotte W. Pratt
Publisher:
WILEY
Biochemistry
Biochemistry
Biochemistry
ISBN:
9781305961135
Author:
Mary K. Campbell, Shawn O. Farrell, Owen M. McDougal
Publisher:
Cengage Learning
Biochemistry
Biochemistry
Biochemistry
ISBN:
9781305577206
Author:
Reginald H. Garrett, Charles M. Grisham
Publisher:
Cengage Learning
Fundamentals of General, Organic, and Biological …
Fundamentals of General, Organic, and Biological …
Biochemistry
ISBN:
9780134015187
Author:
John E. McMurry, David S. Ballantine, Carl A. Hoeger, Virginia E. Peterson
Publisher:
PEARSON