Given the following two half reactions write a balanced oxidation-reduction reaction that occurs between sulfite and Ru3+ in acidic solution. Recall that a good way to proceed is to balance each half reaction in acidic solution, adjust one or both to have the same number of electrons gained as lost, and then add them together .. SO32-→ SO42- and Ru3+ → Ru2+ A) H2O + SO3²- + Ru3+ Ru2+ + SO42- + 2H* B) 6 H2O + 2 SO32- + Ru3+ → Ru2+ + 2 SO42- + 12 H* C) H2O + SO3²- + 2 Ru3+ → 2 Ru²+ + SO42- + 2H* A) H2O + SO3²- + 2 Ru3+ → 2 Ru²+ + SO4²- + 2e¯ + 2H*

When the following skeletal equation is balanced under acidic conditions, what are the coefficients of the species shown? Bro3 + H2SO3 Br + so,2- -> Water appears in the balanced equation as a (reactant, product, neither) with a coefficient of (Enter 0 for neither.) Which species is the oxidizing agent?

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Which of the following is a balanced half reaction in basic solution? O Cl2 + 60H¯ → CIO, + 5e¯ + 3H20 O Cl2 + 12 OH →2 CIO, + 10e¯+ 6H20 O Cl2 + 6H20→2 CIO, + 12H* + 10e- O Cl2 + 3H20→ CIO, + 6H* +5e

Use the References to access important values if needed for this question. Enter electrons as e", The following skeletal oxidation-reduction reaction occurs under acidic conditions. Write the balanced REDUCTION half reaction. 103 + Ni2+ I2 + NiO2 Reactants Products

Explain  well with step by step  answer.

the reactions listed below do not take place.Explain WHY.(for each one seperately) (DO NOT TRY TO BALANCE them , balancing is not the problem)     MnO4-1 + Fe+3 + H+ (water)→ MnO2 + Fe+2 +K+ +H2O

Give answer to all parts?

Is Help I Net ionic/skeletal equation Reduction/oxidati on half reaction (circle one) Reduction/oxidati on half reaction (circle one) Overall balanced equation Net ionic/skeletal equation Reduction/oxidati on half reaction (circle one) Reduction/oxidati on half reaction (circle one) Overall balanced equation TCO4 + Sn²+ Tc++ + Sn** (acidic) Se + Cr(OH)3 Cr + Se03² (basic) MacBook Pro Request edit access Share