Given the diagram below, water is acting as a + H H H H an acid because it donates a hydrogen ion a base because it donates a hydrogen ion O a base because it accepts the hydrogen ion O an acid because it accepts a hydrogen ion

Part A Mark with the green check to indicate that the given direction of electron flow in the following set of molecules using curved arrows notation is correct and with the red X label to indicate when incorrect. Drag the appropriate labels to their respective targets. ► View Available Hint(s) X X X H₂C X CH₂ H₂C Reset Help You labeled 2 of 7 targets incorrectly. Electrons can only be shown to migrate if there is an atomic p orbital to move them to. Moving a lone pair electrons to form a new π bond can only occur if the atom accepting

i need help with the last two structures on the left and right please

Ss important values if needed for this question. In which of the following pure compounds would intermolecular hydrogen bonding be expected? (Select all that apply.) CH3CH2CH2CH2CH2COCH3 CH3CH2CH2CH2CH2COH H. CH2CH3 OCH3CH2CH2OH ONone of the Above

Could we cut just one bond in the "starting" molecule shown in the drawing area below to create this "target" molecule? The target molecule. If so, highlight the bond to be cut. If not, check the box under the drawing area that says Not possible. Note: it's OK if cutting the bond creates more than one molecule, as long as one of them is the target molecule. Not possible. X H H-C-H H-O-H H 3 Note for advanced students: what we mean by "cutting" the bond here is breaking the bond and attaching H atoms to each dangling end, like this: H H-C-0-H H

a) Draw one isomer of C6H14. b) Draw one isomer of C6H12- c) Draw one isomer of C6H140 that exhibits hydrogen bonding. d) Draw one isomer of C6H140 that is not capable of hydrogen bonding. BONUS: Show all locations of possible hydrogen bonding for the C6H140 isomer that you drew above in part c.

can you please please answer everything in the image attach please write clearly and neatly and not messy so its easy to read and understand   please answer fast