Given the declarations struct NodeType { int       data; NodeType* link; }; NodeType* headPtr;   // External pointer to a linked list NodeType* p; Write the code that would sum all the elements in the list.

C++The List class represents a linked list of dynamically allocated elements. The list has only one member variable head which is a pointer that leads to the first element. See the following code for the copy constructor to List. List (const List & list) {          for (int i = 0; i <list.size (); i ++)       {                    push_back (list [i]);           } } What problems does the copy constructor have? Select one or more options: 1. List (const List & list) {} does not define a copy constructor. 2. The list parameter should not be constant. 3. The new elements will be added to the wrong list. 4. Copy becomes shallow rather than deep. 5. The copy will create dangling pointers. 6. Copying will create memory leaks. 7. The condition must be: i <size () 8. head is never initialized.

In c++, how do I display the last node in a linked list?

struct insert_at_back_of_sll { // Function takes a constant Book as a parameter, inserts that book at the // back of a singly linked list, and returns nothing. void operator()(const Book& book) { /// TO-DO (3) /// // Write the lines of code to insert "book" at the back of "my_sll". Since // the SLL has no size() function and no tail pointer, you must walk the // list looking for the last node. // // HINT: Do not attempt to insert after "my_sll.end()". // ///// END-T0-DO (3) ||||// } std::forward_list& my_sll; };