Given that the electric field in slab 1 is -(sigma)/ 4*e_0 z-hat direction and the electric field in slab 2 is - (sigma)/ 3*e_0 z-hat direction. The bound surface charges were found to be -(sigma)/4 for slab 1, -(sigma)/6 for slab 2, and the boundary in between slab 1 and slab 2 is - 5(sigma)/12. The bound volume charge is 0. Question: Now that you know all the charge (free and bound), recalculate the field in each slab, and confirmyour answer to the electric field given above.

Needs Complete typed solution with 100 % accuracy.

Consider an infinite sheet of charge in the xy-plane with uniform charge density Ps. The charge associated with an elemental area ds is: P(0, 0. A)

In the early 1900's Robert Millikan discovered the peculiar property that charge came in little packets, no smaller than e = 1.602 x 10-19 C -- he had measured the charge of the electron. Here's (roughly) how he did it.  He removed an electron from an initially neutral droplet of oil with diameter 0.5 ??μm. In a vacuum, he positioned the droplet between two metallic plates separated by 6 mm and fiddled with the potential (voltage) across the plates until the droplet would hover against the force of gravity. Droplets of this size with +e charge would hover, but only for a particular voltage (otherwise they would sink or rise).  Given the parameters stated here, and the fact that the density of the oil was 831 kg/m3, what was the voltage that made the droplets hover? (give your answer with 0.1 V precision)