College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- Charge is distributed throughout a spherical shell of inner radius ₁ and outer radius r2 with a volume density given by p= Por1/r, where po is a constant. Following the next few steps outlined, determine the electric field due to this charge as a function of r, the distance from the center of the shell. Hint a. Let's start from outside-in. For a spherical Gaussian surface of radius r>r2, how much charge is enclosed inside this Gaussian surface? Hint for finding total charge Qencl (Answer in terms of given quantities, po, r1, 72, and physical constants ke and/or Eo. Use underscore ("_") for subscripts, and spell out Greek letters.) b. What is the electric field as a function of r for distances greater than r₂? Finish the application of Gauss's Law to find the electric field as a function of distance. E(r> r₂) c. Now let's work on the "mantle" layer, r₁arrow_forwardanswer is not 1.62*10^-6 and is not 4011.86 and is not 20131.55 and i will dislike of you put any of these answers and u need to give a numerical answer (not an equation with variables) otherwise i will dislikearrow_forwardProblem Using the method of integration, what is the electric field of a uniformly charged thin circular plate (with radius R and total charge Q) at xo distance from its center? (Consider that the surface of the plate lies in the yz plane) Solution A perfect approach to this is to first obtain the E-field produced by an infinitesimal charge component of the charge Q. There will be several approaches to do this, but the most familiar to us is to obtain a very small shape that could easily represent our circular plane. That shape would be a ring. So for a ring whose charge is q, we recall that the electric field it produces at distance x0 is given by E = (1/ )(xOq)/( 2472) Since, the actual ring (whose charge is dq) we will be dealing with is an infinitesimal part of the circular plane, then, its infinitesimal electric field contribution is expressed as = (1/ )(x0 24 We wish to obtain the complete electric field contribution from the above equation, so we integrate it from 0 to R to…arrow_forwardPlease write you answers neatly and answer all parts.arrow_forwardAn infinite cylinder of radius R has a charge density given by p(r) = ar³, where r is the perpendicular distance from the axis of the cylinder, and a is a constant. Show that the electric field for r > R given by aRT E(r) : 7€or is the same as that obtained if all the charge is concentrated in an infinitely thin wire.arrow_forwardneeds complete typed solution with 100 % accuracy.arrow_forwardDensity, density, density. (a) A charge -328e is uniformly distributed along a circular arc of radius 6.00 cm, which subtends an angle of 72°. What is the linear charge density along the arc? (b) A charge -328e is uniformly distributed over one face of a circular disk of radius 3.50 cm. What is the surface charge density over that face? (c) A charge -328e is uniformly distributed over the surface of a sphere of radius 2.00 cm. What is the surface charge density over that surface? (d) A charge -328e is uniformly spread through the volume of a sphere of radius 3.30 cm. What is the volume charge density in that sphere? (a) Number Units (b) Number Units (c) Number Units (d) Number Unitsarrow_forwardNeed this with explanationarrow_forwardSuppose we have a charge, q1=1 μC. This charge makes an electric field some distance r=60 cm away from it. Now suppose our measurement of q1 is only accurate to within 0.1 μC, and our measurement of r is only accurate to within 2 cm. What is the uncertainty in our field calculation due only to the uncertainty in the charge separation r? for the uncertainty of q I got 2500 N/C. I keep getting 1667.67 N/C for the uncertainty for the separation of r but that is wrongarrow_forwardRound to three significant figuresarrow_forwardGiven a charge Q1=50nC located at the XY coordinates (5m, 10m) and a charge Q2= -20nC located at the X, coordinates (-3m.-1m). The field point has coordinates (-3m, 4m). Find the Total Efield?arrow_forwardUse Gauss's law to find the electric field at the field point in the following case. The distance between the field point and the surface of the conductor is d. A semi-infinitely large conductor with surface charge density o. Field point d х Conductorarrow_forwardarrow_back_iosSEE MORE QUESTIONSarrow_forward_ios
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