Given P(A) = 0.6 and P(A and B) = 0.2 and P(B) = 0.6, then P(A/B) = 0.3 0.3333333... 0.4 0.8333333...

how is 0.46= .32276 because on the z table it's 32.64 so where does the .32276 come from

In Exercises 5–16, use analysis of variance for the indicated test. Lead and Verbal IQ Scores Example 1 used measured performance IQ scores for three different blood lead levels. If we use the same three categories of blood lead levels with measured verbal IQ scores, we get the accompanying Minitab display. (The data are listed in Data Set 7 “IQ and Lead” in Appendix B.) Using a 0.05 significance level, test the claim that the three categories of blood lead level have the same mean verbal IQ score. Does exposure to lead appear to have an effect on verbal IQ scores? Minitab

3. A coffee chain owner is concerned with the proportion of people who would rather order a coffee from another store. The corporate office tells her that from a separate large-scale study, they found the true proportion to be p = 0.6. As she wants to estimate this proportion herself, she asks 20 people in line whether they would switch and records a ‘1’ if they said “Yes” and records a ‘0’ otherwise. (a) Based on this study, what is the approximate distribution of the sample proportion pˆ? State all parameters and assumptions required for your answer. (b) The store owner wants to determine the cutoff point for the sample proportion for which the probability of observing a larger sample proportion is 0.50. That is, find the value ‘a’ such that P(ˆp > a) = 0.50. Show all your work. Explain how you could have found your answer immediately without using the Normal probability table and using a property about the Normal distribution.