Given following data, calculate a. Average specific gravity b. Average absorption value I. DATA TO BE GATHERED:1. Mass of oven-dry test sample in air, g (A)6.19 grams%3D2. Mass of saturated-surface-dry test sample in air, g (B)3. Mass of saturated test sample in water, g (C)6.96 grams3.80 grams%3D

Answered: Image /qna-images/answer/7a74b3ba-8595-4fd0-b7ca-4582adbd8d98.jpg

Answered: Given following data, calculate a.…

Engineering

Civil Engineering

Given following data, calculate a. Average specific gravity b. Average absorption value

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: What are the forces that governs the concept of infiltration in the soil

A: Its a phenomenon which defines the soil ability to allow motion of a water into and through the…

Q: How does an estimate of chlorinity allow us to determine salinity? Explain what principle is…

A: Chlorinity is the weight of chlorine molecules in grams per kilogram of saltwater or seawater after…

Q: MOITAKIMAKS MUERT GIM 1.) DETERMINE THE COEFFICIENT OF PERMEABILITY FROM THE FOLLOWING DATA (MM/S)…

Q: Describe about the Ice lens formation by capillary movement of groundwater into zone of freezing.

A: When ice gets accumulated in soil vertically in the capillary ground movement and gets freeze…

Q: A course sand sample is placed in the constant permeameter test. What is the coefficient of…

Q: CALCULATE THE MIDSPAN VALUE OF 5.7m EIY Wo = 109.6 km 5.7m B

Q: n = Gs= Saturation =

A: n = porosity it ranges from 0 to 100 % Gs = specific gravity e = void ratio ρ = density of soil γ =…

Q: The working charge of a four foot adsorption bed is 32.0%. The MTZ and heel were determined to be 2…

Q: For a permeability test, what most likely will be the temperature correction for a permeability test…

Q: U.S.W.L H L D.S.B.L. L Percolation U.S.W.L. H L D.S.B.L.

A: Bligh Creep Theory The length of the seepage path transversed by the water is known as the length of…

Q: A 1:5 m STEP 1) 1. Magni huele of the Horizon hol componant of the forre AB - 2.5 89 A FH Fiq:…

Q: for B, it says moisture range. so I am expecting an interval. Can I ask how did 8.2 came?

A: This question is related to the Soil Mechanics from Civil Engineering. This is combined problem if…

Q: 2. A subtense bar has a length of 2m measured by theodolite. Determine the values of D. A1 = 04 80’…

Q: Blows Moisture Content,%

Q: Solve the question in the image.

A: Over all efficiency for the control device can be given asηo=∑mass ratio×efficency %

Q: Flocculation is very important in dewatering process. With special reference to the standard…

A: The water treatment process is a very progressive process where to achieve clear water we follow the…

Q: The back fill material for a vibroflotation project has the following grain sizes. D10 0.11 mm…

A: Find sorting coeffficient

Q: Seepage velocity is: a Equal to Darcy velocity b Greater than Darcy velocity c Smaller than Darcy…

Q: 1. Percent passing on sieve 600um Weight Individual Cumulative Percent Sieve Retained Percent…

A: Given Seives size and weight retained on each seive. To Determine Percent passing on seive 600um

Q: How can we increase collection efficiency in electrostatic precipitation?

A: Solution: Each and every set of the T-R set powers a particular section of an electrostatic…

Q: Convert the following moisture content as indicated. Show your solutions. a. 18% wb to MCdb b. 26%…

Q: With given data mc = 35g , mc + w = 520 g , mc + d = 472 g , calculate total evaporable moisture,…

A: Given data- mc = 35g mc + w = 520 gmc + d = 472 gTo Find-total evaporable moisture, surface…

Q: A tracer takes I00 days to travel from Well-I to Well-2 which are 100 m apart. The elevation of…

Q: In the figure shown, theodolite is being set up at point "A" and "C", and subtense bar at point "B".…

A: To Determine :- a) What is the horizontal distance from A to C? b) What is the difference in…

Q: Which of the following statements is INCORRECT? O During dry periods, surface cracks that develop on…

A: Infiltration is the process by which water on the ground surface enters into the soil.

Q: A: Density bottle test: Sample 1: Dal = 0.9982 x (83.49-62.12) (251.3162.12) - (264.41-8 = 2.58 g/ml…

A: SampleDensity, g/cc12.5822.6132.6242.5352.5662.57

Q: 02. A ring infiltrometer (inside area is 962 cm²) test was made on a soil with the results shown in…

Q: Compare optimum moisture content with wilting point water content? Subject: Irrigation Engineering…

A: Introduction : Optimum moisture content : The maximum dry unit weight that a soil can be compacted…

Q: Describe about the Ice lens formation in a frozen soil.

A: Ice lenses are ice bodies produced when moisture accumulates in a localized area, diffused within…

Q: please calculate the absorption and surface moisture content. thank you!

A: Given data-

Q: An aluminum alloy pipe with an outside diameter of 4.9 in. and a wall thickness of 2/16 in.…

A: Outside diameter = 4.9in wall thickness = 2/16in L = 21ft WA = 12 lb/ft WB = 18 lb/ft It has been…

Q: A dry granite rock weighs 26 N. When it was submerged for 24 hours, its weight increased to 30 N.…

A: Given data- Initial weight of the rock w1=26NFinal weight of the rock w2=30NTo Find-Absorption of…

Q: In a constant head permeability test, if the discharge coming out of the sample is 0.35 cm³/s find…

A: Discharge Q=0.35 cm3/sLength L=30 cm,Area A=250 cm2Head loss per unit length i = 0.25Coefficient of…

Q: explained Pooling layer

A: The size of the feature maps is reduced by pooling layers. As a result, it lessens the quantity of…

Q: Read the question carefully and give me right solution according to the question. In a two-peg test…

A: Reading at point A=2.93 m Reading at point B=2.14 m

Q: An amount of Sand weighs 500g in stock condition and 480 g in oven dry condition. If absorption…

A: solution Given the weigth of the samd in stock condition W=500gand in oven dry condition Wd=480g

Q: The Hydraulic Oedometer is set with the top drainage valve closed and the bottom drainage valve…

Q: Design a grit chamber for a conventional wastewater treatment plant to treat wastewater from a…

A: Considering the population of the area is 50000. Average quantity of sewage, considering sewage…

Concept explainers

Principles of Seepage

In hydrology, when water flows down in a pore or crack of unsaturated soil due to gravity, the deep layer of soil is called seepage. It is the slow movement of water in the soil layer. Seepage is mainly found near hydraulic structures and is responsible for the stability of earthen-type hydraulic structures.

Question

Given following data, calculate

a. Average specific gravity
b. Average absorption value

I. DATA TO BE GATHERED:
1. Mass of oven-dry test sample in air, g (A)
6.19 grams
%3D
2. Mass of saturated-surface-dry test sample in air, g (B)
3. Mass of saturated test sample in water, g (C)
6.96 grams
3.80 grams
%3D

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step by step

Solved in 2 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

Following are law or theory related to seepage problems which are :- Darcy law Bernoulli Theorem Newton third law of motion Stokes Law
Situation 3: A calibrated test of a 0.00785 m² circular sharp-edge orifice in a vertical side of a large tank showed a discharge of 22,300 N of water in 1 minute and 40 seconds at a constant head of 1.20 m. Measurement of the jet showed that it traveled 1.92 m horizontally while dropping 0.8 m. 6. Determine the coefficient of discharge. a) 0.621 b) 0.597 c) 0.649 d) 0.721 7. Determine the coefficient of velocity. a) 0.84 b) 0.93 c) 0.74 d) 0.98 8. Determine the coefficient of contraction. a) 0.77 b) 0.97 c) 0.61 d) 0.67 B
A primary clarifier is to be designed to treat a municipal wastewater. The influent to the clarifier has a flow rate of 7570 m³/d and a total suspended solids concentration of 320 mg/L. A laboratory settling test was performed with the following results: Suspended Solids Concentration (mg/L) at Given Depths Sampling Depth (m) Time (min) 0.61 1.22 246 2.44 272 243 1.83 3.05 10 230 262 282 20 157 195 230 253 30 115 160 211 221 230 45 90 134 163 179 195 60 48 102 131 154 170 90 29 58 86 115 141 (a) Determine the design overflow rate and detention time assuming 65% of the suspended solids are to be removed. Use typical scaling/safety factors as appropriate. (b) Determine the required diameter (to the nearest 0.1 m) and the required depth (to the nearest 0.01 m) for the clarifier.
Two flow lines for seepage across an interface between two soil medium having different coefficient of permeability is as shown in the figure below. The entrance angle at the interface is 60° then: k, =1.0 x 10° m/s k -4 x 10 m/s (1) a (2) The exit angle az at interface is 67,55°, A Correct Option B The exit angle az at interface is 81.79, Correct Option The change in exit angle if 'k2' is reduced by 25% is 2.68°. D The change in exit angle if 'k2' is reduced by 25% is 1.78°.
Determine bulk unit weight if dry unit weight 16 KN/m3 water content 0.44
What diameter would a circular clarifier have to be to remove 50 μm particles with 75% efficiency from a 4 MGD (million gallon per day) flow? Assume the particle specific gravity is 1.5 and the temperature is 10°C. Answer: 18 m
Determine the average precipitation
Please provide solution asap
Discuss about Overconsolidation Ratio
1. Percent passing on sieve 4.75mm Weight Individual Cumulative F Sieve Retained Percent Percent (g) 4.75mm 31.5 2.36mm 67.6 1.18mm 96.5 600um 111.1 300um 60.5 150um 115.6 75um 17.5 pan 31.5 Oa. 93.70 ) b. 90.70 Oc. 97.70 d. 99.70