Given an equal tangent vertical curve, in feet, with the following known information: STAA (Beginning of Curve) = 13+00 o Elevation A = 220.00 feet o L=900.0 feet G₁ = -4.25% and G₂ = +3.25% What is elevation of the low point on the curve, in feet? . O 220.00 209.76 209.16 O 215.51

For your Assignment 5, provide what is required by the problem. PI Elev 108.00m 1.50m -3% +6% 8.00m A Sta 1+060 PT PC Sta 1+000 Elev 100.00m Answer the following: • What is the total length of the curve in meters? • What is the length of the first curve in meters? • What is the length of the second curve in meters? • What is the elevation of point A? • What is the distance of the highest point from PC in meters? • What is the elevation of the highest point?

A-2.50% grade meets a +1.75% grade at station 44+25 and elevation 3385.74 ft, 400-ft curve, stakeout at half stations. Part A Determine the elevation at the low point of the curve Express your answer in feet to six significant figures. ΠΗΓΙΑΣΦ Elev = + ft

Simple Curve A railway curve is to connect intersecting tangents with the following design data: Back tangent = N 20° 25' E Forward tangent = S 49°35' E Degree of curve = 5⁰ Design speed = 70 Kph Station PI = 5+555.55 1.Determine the length of line from PC to Pl. a) 234.67m b) 244.67m 2.Compute the straight distance from PC to PT. a) 402.34m b) 375.60m c) 245.89m d) 327.42m c) 389.78m d) 423.67m 3. If the width of the land intended for the railway is 10m, determine the area of land from PC to PT. a) 4,456.56 sqm b) 3,456,43 sqm c) 5,112.34 sqm d) 4,399.92 sqm 4.How long would a 300m long train able to leave the curve completely. a) 25.67 sec b) 38.06m sec c) 40.34 sec d) 29.67 sec

. A curve with radius (R) of 700.00 feet and a central angle (I) of 450 00’ 00” has a PC station of 10+00.00. The equation station at the PT is:   A.          16+35.30 back = 16+70.94 ahead B.          16+28.32 back = 16+62.74 ahead C.          16+14.18 back = 15+86.43 ahead D.          15+97.34 back = 15+86.43 ahead

Part A Compute the passing sight distance available given a 435-ft curve, grades of g₁ = +2.00% and 92 = -1.50%, VPI at station 96+80, and elevation 845.26 ft, stakeout at full stations. (Assume h₁ = 3.25 ft and h₂ = 4.50 ft.) Express your answer in feet to five significant figures. IVE ΑΣΦ | S= vec ? ft

subject: surveying 2. if possible please give a detailed answer for me to un

Given a simple circular curve, in feet, with the following known information: o | = 45°2O'15" Da = 5°00'00" o STA P.I. =45+20.25 What is the length of the long chord in feet? O 883.28 O 883.56 O 906.75 O 907.04

Two tangents intersect at station 26+050. A compound curve laid on their tangents has the following data: I1 = 31deg; I2 = 36 deg; D1 = 3deg; D2 = 5deg, PC = 25+828.88, total length of the common tangent = 180.40. Compute the stationing of the P.T. (Format: 00+000.00)

2. In the figure shown AB = 103.20m with A at station 10 + 158.93. The angle VAC is 15'21' and angle VBC is 18°31', where Cis the point to which a simple curve is to be constructed tangent to the line AB. a) Determine the radius of the curve b) Determine the stationing of point C. c) Determine the stationing of P.T. 10+158.93 A 521'C 18 31B P.C.