A parabolic curve having a forward tangent of -3% intersects a back tangent of 6.5% at sta 10=800 whose elevation is 5260m. If the length of the curve is 400m, Find the stationing of the highest point of curve. a.10+877.5 b. 10+875.6 c. 10+871.1 d. 10+873.7

A simple curve connects two tangents AB and BC with bearings N 36°12' E and N 58°53' E respectively. The PC is a A which is at Sta. 5+234.65 and the B is at Sta. 5+265.09. * Find the radius of the curve. a. 169. 09 m c. 201.12 m b. 137.85 m d. 151.76 m * Using chord basis, compute the degree of the curve. c. 6.78° a. 5.70° b. 7.56° d. 8.31° * Find the external distance. c. 3.36 m a. 2.75 m b. 3.02 m d. 4.01 m * Find the middle ordinate. c. 2.69 m a. 2.96 m b. 3.93 m d. 3.30

A simple curve with tangents AV and VE have azimuth of 260°48' and 285°40' respectively. Point B is taken along AV and C along VE. The azimuth and distance of BC are 272°16' and 61.22 m respectively. The degree of curve is 5°. The stationing of point B is 8 + 126.3. 1. Determine the radius of the simple curve. a. 184.99 m b. 229.18 m c. 314.67 m d. 287.25 m 2. Determine the length of curve. a. 99.47 m b. 85.45 m c. 51.93 m d. 79.12 m 3. Determine the stationing of PT. a. 8 + 155.21 b. 8 + 208.98 c. 8 + 311.63 d. 8 + 194.47

4. The broken back curve shown is to be replaced by a compound curve R2 = 1.8R1. T1=250m, T2=350m, Δ1/2=30°, Δ2/2=20°, and short tangent =45m. Determine: a.new values of radii b. new values of tangents (ans: a) R1=1101.928m R2=1983.470m,and m=295.261m and n=349.739m)