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Given an array of n objects, you need to decide if there is an object which is present more than n/2 times. The only operation by which you can access the objects is a function f, which given two indices i and j, outputs whether the objects at positions i and j in the array are identical or not. Give an O(n log n)-time divide-and-conquer algorithm for this (where each call to f is counted as one operation).

Given an array of n objects, you need to decide if there is an object which is present more than n/2 times. The only operation by which you can access the objects is a function f, which given two indices i and j, outputs whether the objects at positions i and j in the array are identical or not. Give an O(n log n)-time divide-and-conquer algorithm for this (where each call to f is counted as one operation).

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Question 1.5 Given an array of n objects, you need to decide if there is an object which is present more than n/2 times. The only operation by which you can access the objects is a function f, which given two indices i and j, outputs whether the objects at positions i and j in the array are identical or not. Give an O(n log n)-time divide-and-conquer algorithm for this (where each call to f is counted as one operation).
Transcribed Image Text:Question 1.5 Given an array of n objects, you need to decide if there is an object which is present more than n/2 times. The only operation by which you can access the objects is a function f, which given two indices i and j, outputs whether the objects at positions i and j in the array are identical or not. Give an O(n log n)-time divide-and-conquer algorithm for this (where each call to f is counted as one operation).
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