Give an explanation as to why a high-speed router's each input port has its own shadow forwarding table.
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Q: Defend the need of a shadow forwarding table in a high-speed router's input ports.
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Give an explanation as to why a high-speed router's each input port has its own shadow forwarding table.
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- A 4480-octet datagram is to be transmitted and needs to be fragmented because it will pass through an Ethernet with a maximum payload of 1500 octets. Show the Total Length, More Flag, and Fragment Offset values in each of the resulting fragments.We mentioned that two types of networks, datagram and virtual-circuit, need a routing or switching table to find the output port from which the information belonging to a destination should be sent out, but a circuit-switched network has no need for such a table. Give the reason for this difference.We have discussed several switching fabrics techniques for the design of a router. Is switching via memory is faster than switching via bus?
- What are the benefits and drawbacks of various access methods based on random access? Why does the slotted ALOHA protocol have twice the channel use of pure Aloha?Suppose a switch is built using a computer workstation and that it can forward packets at a rate of 500,000 packets per second, regardless (within limits) of size. Assume the workstation uses direct memory access (DMA) to move data in and out of its main memory, which has a bandwidth of 2 Gbps, and that the I/O bus has a bandwidth of 1 Gbps. At what packet size would the bus bandwidth become the limiting factor?It is possible to describe an isochronous connection and a synchronous connection by comparing and contrasting these two kinds of connections.
- Which issues with the router's layer 2 protocol have been found up to this point? In what ways does this new information have an impact? Why does the ICMP request of a PPP-encapsulated router continue to function after the subnet of the serial interface has been changed?Circuit-switched networks, unlike datagram and virtual-circuit networks, do not require a routing or switching table to determine the output port from which the information pertaining to a destination can be transferred. Let us know what's behind this discrepancy.The minimum number of columns in a datagram network is two; the minimumnumber of columns in a virtual-circuit network is four. Can you explain thereason? Is the difference related to the type of addresses carried in the packetsof each network?
- The minimum number of columns in a datagram network is two; the minimum number of columns in a virtual-circuit network is four. Can you explain the reason? Is the difference related to the type of addresses carried in the packets of each network?Design an Ethernet network to connect a single client PC to a single server. Both the client and the server will connect to their respective workgroup switches via UTP. Their workgroup switches are connected directly by a trunk link. The two switches are 900 meters apart. They need to communicate at 800 Mbps. Your design will specify the locations of any switches and the transmission link between the switches. Then add another client next to the first client. This client will also communicate with the server and will also need 800 Mbps in transmission speed. Again, your design will specify the locations of switches and the transmission link between the switches.It is obvious that a router or a switch needs to do searching to find information in the corresponding table. The searching in a routing table for a datagram network is based on the destination address; the searching in a switching table in a virtual circuit network is based on the combination of incoming port and incoming VCI. Explain the reason and define how these tables must be ordered (sorted) based on these values.
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