College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- An oscillator has an equation of x(t) = (0.12 m) cos( 4.2t) Assuming that w is in SI units (radians/s), find the period of oscillation in seconds with two digits of precision. Your Answer: Answerarrow_forwardYour grandfather clock's pendulum has a length of 0.9930 m. a. If the clock runs slow and loses 23 s per day, how should you adjust the length of the pendulum? Note: due to the precise nature of this problem you must treat the constant g as unknown (that is, do not assume it is equal to exactly 9.80 m/s2). Express your answer to two significant figures and include the appropriate units. Enter positive value in case of increasing length of the pendulum and negative value in case of decreasing length of the pendulum.arrow_forwardA pendulum has a length of 0.00272 m. What is the period of its oscillation?arrow_forward
- A spring is hanging down from the ceiling, and an object of mass m is attached to the free end. The object is pulled down, thereby stretching the spring, and then released. The object oscillates up and down, and the time T required for one complete up-and-down oscillation is given by the equation T = 2л√/m/k, where k is known as the spring constant. What must be the dimension of k for this equation to be dimensionally correct? O [T] O [T]² O [M] O [M]/[T] O [T]/[M] O [M]/[T]² O [T]²/[M]arrow_forwardIn the figure below, what do the quantities do A and B refer to? Position (cm) 5 A 4 3 2 BI -2 -3 -4 -5 2 4 A refers to: ○ Period None Amplitude ○ Acceleration B refers to: Amplitude ○ 1/2*Amplitude ○ Period O None 6 Time (sec) 8 10 12 The period of oscillation in the above graph is 2π sec, what is the frequency of oscillation?arrow_forwardHow long must a simple pendulum be if it is to make exactly one swing per five seconds? (That is, one complete oscillation takes exactly 10 s.) Express your answer to two significant figures and include the appropriate units. HA ? = 1 Value Units Submit Request Answerarrow_forward
- A 52.6 cm-long pendulum takes 2.50 minutes to undergo 104.1 complete oscillation cycles. (a) Compute the pendulum's period (in s). (b) Determine the acceleration due to gravity (in m/s²) at the place where the pendulum is located. m/s²arrow_forwardA pendulum is formed by placing a horizontal axis at various positions of a measuring stick of length 108 cm. What is the period in seconds of the pendulum when the axis is placed at the 81.0-cm mark?arrow_forwardA simple pendulum has a length of 52.6 cm and makes 81.6 complete oscillations in 2.00 min. (a) Find the period of the pendulum. (b) Find the value of g at the location of the pendulum. m/s2arrow_forward
- The cord of the machine is moved 4 cm off the equilibrium position and released. After 1.5 s from the moment of start-up, the ball reaches equilibrium. Determine the length of the pendulum! (g = 10 m / s2).arrow_forwardProblem #10: A pendulum with a period of 2.00000 s in one location (g=9.80m/s2) is moved to a new location where the period is now 1.99748 s. a) What is the acceleration due to gravity at its new location? (report your answer to at least 5 decimal places)arrow_forwardThe frequency of oscillation of a swing on a different world is 2.3 Hz, and the acceleration due to gravity is 470 m/s2. Calculate the length of the swing. L = marrow_forward
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