l4//me shear and bending moment diagram as shown in figure. by graphical method. 132.5KN 122.5KN.m ) sgN/m b itwd L oe—dine—d G4//Draw shear and bending moment diagram as shown in figure. by graphicalmethod.132.5KN122.5KN.m15KN/m3 m3 m3 m

A pin support will exert both the horizontal and vertical components of a reaction. Let the support…

Answered: G4//Draw shear and bending moment…

G4//Draw shear and bending moment diagram as shown in figure. by graphical method. 132.5KN 122.5KN.m 15KN/m - 3 m - 3 m 3 m 3 m-

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter10: Statically Indeterminate Beams

Section: Chapter Questions

Problem 10.4.6P: A beam with a sliding support at B is loaded by a uniformly distributed load with intensity q. Use...

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Use the graphical method to construct the shear-force and bending-moment diagrams for the beam shown. Let a = 5 m, b = 3 m, PB = 55 kN, Pc = 75 kN, and PE = 25 kN. Construct the shear-force and bending-moment diagrams on paper and use the results to answer the questions in the subsequent parts of this GO exercise. a PB Answer: Ay = i BO PB a B Pc a Calculate the reaction forces Ay and Dy acting on the beam. Positive values for the reactions are indicated by the directions of the red arrows shown on the free-body diagram below. (Note: Since Ax = 0, it has been omitted from the free-body diagram.) D Pc D a D₂ PE a PE E kN, Dy= i -x E X kN.
Use the graphical method to construct the bending-moment diagram and identify the magnitude of the largest moment (consider both positive and negative). The ground reactions and the shear-force diagram are provided. M = 14 kN-m Ay = 3.54 KN Dy = 32.46 kN Units: KN Ay M 4m O 31.52 kN-m O 20.0 kN-m O 33.6 kN-m 23.2 kN-m O 26.1 kN-m B Ay 4 m 15 kN C A, 4 m A,-15 7 kN/m D 3 m 21 A₁-15 E X
For the simply supported beam subjected to the loading shown, derive equations for the shear force V and the bending moment M for any location in the beam. (Place the origin at point A.) Let a-3.25 m, b=4.75 m, Pg - 35kN, and Pc = 80kN. Construct the shear- force and bending-moment diagrams on paper and use the results to answer the questions in the subsequent parts of this GO exercise. A Ay- 58.66 - Dy- Calculate the reaction forces A, and Dy acting on the beam. Positive values for the reactions are indicated by the directions of the red arrows shown on the free-body diagram below. (Note: Since Ax = 0, it has been omitted from the free-body diagram.) Answers: a 56.33 (a) V= (b) V- (c) V- B i i PB B kN с kN C Determine the shear force acting at each of the following locations: (a) x-2m (b)x - 4 m (c) x-8 m Note that x = 0 at support A. When entering your answers, use the shear-force sign convention detailed in Section 7.2. 3 3 3 KN D b kN D ·x Dy
Q-3 Write the shear and moment equation and sketch them 30kN 20 NIM 5m 4m
50 kN *** w 1* 4 m 3 kN/m 5 75 kN 37° Draw the shear force diagram and the bending moment diagram for the anchor beam below.
For the simply supported beam subjected to the loading shown, derive equations for the shear force V and the bending moment M for any location in the beam. (Place the origin at point A.) Let w = 20.0 kips/ft, a=6.0 ft, and b=20.5 ft. Construct the shear-force and bending-moment diagrams on paper and use the results to answer the questions in the subsequent parts of this GO exercise. a A B a W Calculate the reaction forces By and Cy acting on the beam. Positive values for the reactions are indicated by the directions of the red arrows shown on the free-body diagram below. (Note: Since Bx = O, it has been omitted from the free-body diagram.) B b b X C X
The simply supported beam is subjected to the force F = 700 N and the uniform distributed load with intensity w = 150 N/m. Draw the shear force and bending moment diagrams (in your homework documentation) and determine the equations for V(r) and M(x). Take a = 0 at point A. 19 F a Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. Variable Value a 5.2 m 2.6 m 3.12 m Support Reactions The reaction at A is N. The reaction at D is N. Shear Force and Bending Moment Equations In section AB: V(x)= N and M(x)= N-m. In section BC: v(x)- N and M(x)= N-m. In section CD: V(x)- N and M(x)= N-m. A
A beam is supported and loaded as shown. In the section of the beam between 'A' and 'B', the equation for the resisting bending moment was determined as: M₁ = -6.5x²+50x. Determine the magnitude of maximum resisting bending moment (Mr,max) in the section. Note: Do NOT include units in your answer Answer: AA B
Q-3 Write the shear and moment equation and sketch them 30 ku 20 NIM 5m de 5m
(a) Develop shear and bending moment diagrams using the graphical method. (b) Determine functions for shear and moment using the method of sections for the region defined by 0
For the simply supported beam subjected to the loading shown, derive equations for the shear force V and the bending moment M for any location in the beam. (Place the origin at point A.) Let w = 20.0 kips/ft, a=6.0 ft, and b=20.5 ft. Construct the shear-force and bending-moment diagrams on paper and use the results to answer the questions in the subsequent parts of this GO exercise. y A A Answers: By a = Calculate the reaction forces By and Cy acting on the beam. Positive values for the reactions are indicated by the directions of the red arrows shown on the free-body diagram below. (Note: Since Bx = O, it has been omitted from the free-body diagram.) = a i B Cy i = W B b W b kips X kips X
Use the graphical method to construct the shear-force and bending-moment diagrams for the beam shown. Let a=4.0 ft, b=8.0 ft, c=4.0 ft, d=3.0 ft, w = 6.5 kips/ft and P = 45 kips. Construct the shear-force and bending-moment diagrams on paper and use the results to answer the questions in the subsequent parts of this GO exercise. a B a W B W C b d For this loading, calculate the reaction forces Ay and Ey acting on the beam. Positive values for the reactions are indicated by the directions of the red arrows shown on the free-body diagram below. (Note: Since Ax = 0, it has been omitted from the free-body diagram.) b C C P C D P Ľ E d E ·x Ey