-Fully explain the following data path for the brach instruction.

Q3) Consider the Shift Register with Load shown in the figure bellow. When load = '0', it operates as a regular shift register. However, if load = '1', din is loaded into the DFFS at the next positive clock transition (thus the initial state of the flip-flops can be programmed). Assuming you have this entity in your project ENTITY MUXED_FF IS PORT (clk, din, d, load : IN STD_LOGIC; q: OUT STD_LOGIC); END ENTITY; Design this component and the top-level design in VHDL using GENERATE directive where the number of stages (default= 4) is defined using GENERIC din(0) din(1) d 9 d d- 0 clk load. din(2) din(3) 1 d d q -dout

A Little boolen algebra. what is the result (in t1) of the instruction xor $t1, $t0, $t0?

How is the one-operand IMUL instruction different from MUL in the way it generates amultiplication product?