ft Given the following vertical curve data: PVI at 7 + 25.712, L= 100, g1 = -3.2%, 82 = +1.8%, and elevation of PVI = 210,440, compute the elevations of the curve low point and even 20- stations. %3D 110 I

Q: A Compound circular curve have: - R1= 290.75 m, Ai= 40' 14', C:= 175 m, - 27 40', Stat. P.C. = 50 +…

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Q: Compute for the length of curve A line of levels was taken at given points on the existing surface…

A: Given data- Four stations and their elevation-To Find-The length of the curve L

Q: The equation station at the PT is:

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Q: A 500-ft curve, 9₁ = -2.00%, 9₂ = +3.00 %, VPI station = 98 + 10, VPI elevation = 5388.26 ft,…

A: g1 = -2.00%g2= +3.00%L = 500ftPvi elevation = 5388.26ftPvi station = 98+10To find:Elevations

Q: Compute the passing sight distance available given a 440-ft curve, grades of g₁ = +2.00% and 9₂…

A: The sight distance available from a point is the distance along the road surface over which a driver…

Q: What is the station of the PT of a horizontal curve with the following data: A=40°50', R=600 ft and…

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Q: Fundamentals of Surveying 1. If the stationing PI of spiral curve is at 13 + 184.43 and if R of a…

A: Given Radius = 273.49 m  Intersection angle = 440  Length of spiral curve = 105 m

Q: A 500-ft curve, 9₁ = -2.00%, g2 = +3.00%, VPI station = 98+10, VPI elevation = 5388.26 ft, stakeout…

A: g1 = -2.00%g2= +3.00%L = 500ftVPI station, Elevation of VPI, To find: Elevation of full stations.

Q: A 500-ft curve, grades of g₁ = +1.50 % and g₂ = -2.50%, VPI at station 96 + 80 and elevation 841.26…

A: The initial grade of the curve = 1.5%The final grade of the curve = -2.50%The station of point of…

Q: The common tangent AB of a compound curve is 76.42-m, with an azimuth of 88°30'. The vertex V being…

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Q: 24.19 Two diverging tangents AV and CV with an angle of intersection AVC of 38°, are to be connected…

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Q: 1. You are traversing along a centerline, (S 45° 00' E), at Station 1+50, you establish a BC, for a…

A: To Determine Length T1 and T2 of the given compound curve.

Q: Grades of +3.00% and -2.00%, sight distance 520 ft, h₁ = 3.50 ft and h₂ = 2.50 ft. Part A What is…

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Q: Given a horizontal simple curve of 431 m, an intersection angle of 32 degrees, and the PI station of…

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Q: 1. A symmetrical parabolic pass through a point of the intersection is 197m 1). Determine the length…

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Q: A 500-ft curve, 91 = -2.00%, g2 = +3.00 %, VPI station = 98 + 10, VPI elevation = 5388.26 ft,…

A: g1 = -2.00%g2= +3.00%L = 500 ftPVI elevation = 5388.26 ftPVI station = 98+10

Q: Compute the passing sight distance available given a 440-ft curve, grades of ₁₂ Express your answer…

A: The sight distance available from a point is the distance along the road surface over which a driver…

Q: A 500-ft curve, grades of g₁ = +2.50% and 9₂ = -3.00%, VPI at station 96 + 80 and elevation 835.26…

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Q: Compute the first three entries in a table for setting out the following vertical curve, at…

A: Length of curve = L L = KA K = 55 A = g1 - g2 = 1.5 + 1.6 = 3.1 L = 55 X 3.1 = 170.5 m

Q: Situation 3: An 80 simple curve connecting two tangents that intersect at an angle of 880 is to be…

A: Given, Degree of simple curve, D1=8°Intersection angle=88°Degree of compound curve, D2=3°6º end…

Q: A highway curve has R = 600 m, I = 20°00', and Pl station = 3 + 290.600 m. What sight distance is…

A: R = 600 mI = 20∘00′  PI station = 3 + 290.600 m.

Q: Problem 3: From the given curve design, data calculate the stations of PC and PT of this horizontal…

A: To find station of P.C & P.T Given R = 380 m Sta P.I = 02+026.55 ( considering it in form of k.m…

Q: 2.50% grade meets a +1.75% grade at station 44+25 and elevation 3385.74 ft, 400-ft curve, stakeout…

A: The elevations and grades at the beginning and end of the curve need to be determined. We will call…

Q: A 500-ft curve, 9₁ = -2.00%, g₂ = +3.00%, VPI station = 98 + 10, VPI elevation = 5388.26 ft,…

A: Given data: Elevation of PVC Station of PVC PVT station

Q: För ån equal tangent vertical curve g1 = -4%, g2 = +3%, L = 300.00 ft, BVC Station = 10+00.00, BVC…

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Q: A Compound circular curve have: - RI = 290.75 m, A1= 40 14', C2=175 m, 2= 27 40', Stat. P.C. = 50 +…

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Q: 2. In the figure shown AB = 103.20m with A at Station 10+158.93. The angle VAC is 15021' and angle…

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Q: The long chord distance from PC to PT of a reverse curve is 180 m. Find the perpendicular distance…

A: T1 = length of 1st tangent T2 = length of second tangent R1= radius of 1st curve R2 = radius of 2nd…

Q: topic: fundamentals of surveying A 3% ascending grade meets a 5% descending grade at station 2+110…

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Q: A vertical summit curve has a backward tangent of+5% and a forward tangent of -8%,what is the…

A: Given:- The grade of the backward tangent = +5% The grade of the forward tangent = -8% The length of…

Q: A Compound circular curve have: - R1= 290.75 m, A= 40' 14', C:-175 m, - 27' 40', Stat. P.C. = 50 +…

A: To Determine 1- Stations of main points. 2- Coordinates of PI, PT, PCC

Q: PI Elev 108.00m 1.50m -3% +6% 8.00m A Sta 1+060 PT PC Sta 1+000 Elev 100.00m

A: The length of the curve is generally referred to as the limit of the total sum of the line segment…

Q: 26.6 The external distance of a simple curve is 15 m. and has central angle of 30°. If the length of…

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Q: IV. Calculation Patan Numbar) • Ic, = 2Rsin(a,/2) • x, = le,cos(a,/2) % = le,sin(a,/2) V. Data and…

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Q: 26.9 A vertical parabolic curve has a back tangent of -5% and a forward tangent of +3%. If the…

A: Note:- Hi! Thank you for the question As per the honor code, We’ll answer the first question since…

Q: A Compound circular curve have: - R1= 290.75 m, A 40' 14', C:=175 m, A2 27 40', Stat. P.C. = 50 +…

A: To Determine 1- Stations of main points. 2- Coordinates of PI, PT,  PCC Azimuth of PC-PCC = 275°22'…

Q: SITUATION. The common tangent AB of the compound curve is 76.42m, with an azimuth of 268030'. The…

A: Answer We are given Common tangent AB Azimuth = 268o30' Tangent AV Azimuth = 247o50'  Tangent VB…

Q: 24.14 Railroad curve with T 300.00 ft, D. 230', and PI station 48+ 00.00 24.13 Highway curve with T=…

A: Dc=2o30''   T=300 ft,  PI=48+00.00R=5729.6Dc=527362.5=2291.84 ftR=2291.84 ftTangent…

Q: Surveying

A: Usibg relation :L=NS22H1+H2H1=eye level=1.5mH2=asphalt level=0

Q: 14 Two tangents that intersect at an angle of 44°36' are to be connected by a compound curve.…

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Q: VPI Station = 59+70 VPI Elevation = 5,893.48' = -2.20% = +3.50% = 1600 91 92 Length

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Q: Given an equal tangent vertical curve, in feet, with the following known information: • STA A…

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Q: A Compound circular curve have: - Ri = 290,75 m, A= 40' 14', C2= 175 m, Stat. P.C. - 50 + 10, P.C…

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