
Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN: 9780134580999
Author: Elaine N. Marieb, Katja N. Hoehn
Publisher: PEARSON
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From the following DNA strand: AAGCTAGGATTGCC How many codons would be present?
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- Protein synthesis is a complicated process involving DNA being transcribed to RNA, which is then translated into amino acids. Complete the DNA-to-amino acid table for three consecutive codons with the appropriate nucleotides and amino acids using a codon table. Nucleotide and amino acid options can be used multiple times or not at all. 5' to 3' DNA strand T T A G A G 3' to 5' DNA strand A A T C T C G C G transcribed mRNA U U A G A G C G C TRNA anticodon A. A U C U G C G amino acid leucine glutamic acid Answer Bank A glutamic acid leucine cysteine arginine proline Uarrow_forwardOriginal sequence: Consider the following coding 71 nucleotide DNA template sequence (It does not contain a translational start): 5’-GTTTCCCCTATGCTTCATCACGAGGGCACTGACATGTGTAAACGAAATTCCAACCTGAGCGGCGT GTTGAG-3’ Question: 4) In a mutant you discovered that the underlined nucleotide has been deleted. What would the resulting peptide sequence be? What type of mutation is this? 5’-GTTTCCCCTATGCTTCATCACGAGGGCACTGACATGTGTAAACGAAATTCCAACCTGAGCGGCGT GTTGAG-3arrow_forwardThe following DNA sequence corresponds to the two extreme ends of a gene's coding region: 10 5' ATG-GAA-CCG Each codon is separated by a dash and the middle of the gene is represented by "...". Refer to the codon table to answer each question. First position (5' end) U 13 C #t A U UUU UUC UUA UUG CUU CUC CUA CUG Phe Leu Leu AUU AUC lle AUA CAG-TGA 3' * $ UCU UCC UCA UCG CCU CCC CCA CCG ully understand the concept covered in this question? ACU ACC ACA 15 Second position C A U ( 49 Ser U Pro Thr 16 UAU UAC UAA stop UAG stop 4- CAU CAC CAA CAG AAU AAC AAA It's Muddy Tyr 17 His Gln Asn Glu Q Search S It's Clear J+ & UGU U UGC C UGA stop A UGG Trp G CGU CGC CGA CGG AGU AGC AGA G LC 18 N Cys Arg Ser * fg U C A G hp U C A a DII Third position (3' end) ✓ Submit Answer C f10 ( O □arrow_forward
- The genetic code is thought to have evolved to maximize genetic stability by minimizing the effect on protein function of most substitution mutations (single-base changes). We will use the six arginine codons to test this idea. Consider all of the substitutions that could affect all of the six arginine codons.(a) How many total mutations are possible?(b) How many of these mutations are “silent,” in the sense that the mutantcodon is changed to another Arg codon?(c) How many of these mutations are conservative, in the sense that an Argcodon is changed to a functionally similar Lys codon?arrow_forwardWhat is the DNA (template) strand of the following DNA (coding) strand: CAGGATGAATTGCTCarrow_forwardUsing the genetic code, interpret the following set of nucleotides. AUGGGUCCAUGGCGUAGGCCAAAUGAUGAGGAAUGAarrow_forward
- Template strand of DNA is: 3’ TACATAACCGGGCCCATATCGGCCATTTGC5’. 2a). Following transcription, what is the total number of codons in the mRNA transcript? 2 b). Where is the start codon located in this mRNA transcript? 2c). Following translation of this mRNA transcript, how many amino acids will the proteincontain and identify the amino acids sequence of this gene from a genetic code table*.*Note= using a genetic code tablearrow_forwardThe sequence of a polypeptide is determined by the order of codons that specify the amino acids in the polypeptide. How many different sequences of codons can specify the polypeptide sequence methionine-histidine-lysine? (Use the table to find the number of possibilities.) SECOND BASE UAU UACFTyrosine (Tyr) UAA -Stop codon UAG -Stop codon UUUL UGU Cysteine (Cys) UCU uc UCA FSerine (Ser) uca Uuc Phenylalanine (Phe) UUAL Leucine (Leu) CAU CAC CAA Glutamine (Gin) CAGF UGA -Stop codon uaa -Tryptophan (Trp) CGU сос CGA FArginine (Arg) CU CU Histidine (His) CuA FLeucine (Leu) Cua) Proline (Pro) CCA cca AAU Asparagine (Asn) AGU Serine (Ser) AGC AUU ACU ACC Threonine (Thr) AACF AAA AAGLysine (Lys) AUC Fisoleucine (lle) AUA Methionine (Met) AUG - Start codon ACA ACG AGA AGGFArginine (Arg) GU GACAspartic acid (Asp) GGA GAA Glutamic acid (Glu) Gaa) GcU -Valine (Val) G GUA GCA FAlanine (Ala) Glycine (Gly) 8. 1 4 THIRD BASE 2. FIRST BASEarrow_forwardGive the coordinate for the last base of the first exon for tra-RB; type a number as in 7,000 (include the comma)arrow_forward
- Insulin is synthesized as preproinsulin, which has 81 amino acids. How many heterocyclic bases must be present in the informational DNA strand to code for preproinsulin (assuming no introns are present)?arrow_forwardA nontemplate strand of bacterial DNA has the following base sequence. What amino acid sequence will be encoded by this sequence? 5′ –ATGATACTAAGGCCC–3′arrow_forwardlook at the code: import random # Define the DNA nucleotidesnucleotides = ["A", "T", "G", "C"] # Define the codon-to-amino acid dictionarycodon_table = { "AUG": "M", # Start codon "UUU": "F", "UUC": "F", "UUA": "L", "UUG": "L", "UCU": "S", "UCC": "S", "UCA": "S", "UCG": "S", "UAU": "Y", "UAC": "Y", "UAA": "*", # Stop codon "UAG": "*", # Stop codon "UGU": "C", "UGC": "C", "UGA": "*", # Stop codon "UGG": "W", "CUU": "L", "CUC": "L", "CUA": "L", "CUG": "L", "CCU": "P", "CCC": "P", "CCA": "P", "CCG": "P", "CAU": "H", "CAC": "H", "CAA": "Q", "CAG": "Q", "CGU": "R", "CGC": "R", "CGA": "R", "CGG": "R", "AUU": "I", "AUC": "I", "AUA": "I", "AUC": "I", "ACU": "T", "ACC": "T", "ACA": "T", "ACG": "T", "AAU": "N", "AAC": "N", "AAA": "K", "AAG": "K", "AGU": "S", "AGC": "S", "AGA": "R", "AGG": "R", "GUU": "V", "GUC": "V", "GUA": "V",…arrow_forward
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